The problem is that the same code that compiles well on Windows, is unable to compile on Ubuntu. Every time I get this error:
cc1: warnings being treated as errors
Now, it's big code base and I don't like fix all the warnings.
Is there any way I can compile successfully in spite of the warnings?
Sure, find where -Werror is set and remove that flag. Then warnings will be only warnings.
You can make all warnings being treated as such using -Wno-error. You can make specific warnings being treated as such by using -Wno-error=<warning name> where <warning name> is the name of the warning you don't want treated as an error.
If you want to entirely disable all warnings, use -w (not recommended).
Source: http://gcc.gnu.org/onlinedocs/gcc-4.3.2/gcc/Warning-Options.html
Remove -Werror from your Make or CMake files, as suggested in this post
If you are compiling linux kernel. For example, if you want to disable the warning that is "unused-but-set-variable" been treated as error. You can add a statement:
KBUILD_CFLAGS += $(call cc-option,-Wno-error=unused-but-set-variable,)
in your Makefile
Thanks for all the helpful suggestions. I finally made sure that there are no warnings in my code, but again was getting this warning from sqlite3:
Assuming signed overflow does not occur when assuming that (X - c) <= X is always true
which I fixed by adding the following CFLAG:
-fno-strict-overflow
-Wall and -Werror compiler options can cause it, please check if those are used in compiler settings.
来源：https://stackoverflow.com/questions/11561261/how-to-compile-without-warnings-being-treated-as-errors