How can I import a .pyc compiled python file and use it

问题

Im trying to figure out how to include a .pyc file in a python script.

For example my script is called:

myscript.py

and the script I would like to include is called:

included_script.pyc

So, do I just use:

import included_script

And will that automatically execute the included_script.pyc ? Or is there something further I need to do, to get my included_script.pyc to run inside the myscript.py?

Do I need to pass the variables used in included_script.pyc also? If so, how might this be achieved?

回答1:

Unfortunately, no, this cannot be done automatically. You can, of course, do it manually in a gritty ugly way.

Setup:

For demonstration purposes, I'll first generate a .pyc file. In order to do that, we first need a .py file for it. Our sample test.py file will look like:

def foo():
    print("In foo")

if __name__ == "__main__":
    print("Hello World")

Super simple. Generating the .pyc file can done with the py_compile module found in the standard library. We simply pass in the name of the .py file and the name for our .pyc file in the following way:

 py_compile.compile('test.py', 'mypyc.pyc')

This will place mypyc.pyc in our current working directory.

Getting the code from `.pyc` files:

Now, .pyc files contain bytes that are structured in the following way:

First 4 bytes signalling a 'magic number'
Next 4 bytes holding a modification timestamp
Rest of the contents are a marshalled code object.

What we're after is that marshalled code object, so we need to import marshal to un-marshall it and execute it. Additionally, we really don't care/need the 8 first bytes, and un-marshalling the .pyc file with them is disallowed, so we'll ignore them (seek past them):

import marshal

s = open('mypyc.pyc', 'rb')
s.seek(8)  # go past first eight bytes
code_obj = marshal.load(s)

So, now we have our fancy code object for test.py which is valid and ready to be executed as we wish. We have two options here:

Execute it in the current global namespace. This will bind all definitions inside our .pyc file in the current namespace and will act as a sort of: from file import * statement.
Create a new module object and execute the code inside the module. This will be like the import file statement.

Emulating `from file import *` like behaviour:

Performing this is pretty simple, just do:

exec(code_obj)

This will execute the code contained inside code_obj in the current namespace and bind everything there. After the call we can call foo like any other funtion:

foo()
# prints: In foo!

Note: exec() is a built-in.

Emulating `import file` like behaviour:

This includes another requirement, the types module. This contains the type for ModuleType which we can use to create a new module object. It takes two arguments, the name for the module (mandatory) and the documentation for it (optional):

m = types.ModuleType("Fancy Name", "Fancy Documentation")

print(m)
<module 'Fancy Name' (built-in)>

Now that we have our module object, we can again use exec to execute the code contained in code_obj inside the module namespace (namely, m.__dict__):

exec(code_obj, m.__dict__)

Now, our module m has everything defined in code_obj, you can verify this by running:

m.foo() 
# prints: In foo

These are the ways you can 'include' a .pyc file in your module. At least, the ways I can think of. I don't really see the practicality in this but hey, I'm not here to judge.

来源：https://stackoverflow.com/questions/34709390/how-can-i-import-a-pyc-compiled-python-file-and-use-it

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python