python, read the filename from directory , use the string in bash script

问题

I am writing a bash script (e.g. program.sh) where I am calling a python code in which a list of files are read from a directory.

the python script (read_files.py) is as following:

import os


def files(path):

    for filename in os.listdir('/home/testfiles'):
        if os.path.isfile(os.path.join('/home/testfiles', filename)):
            yield filename

for filename in files("."):

    print (filename)

Now I want to keep the string filename and use it in the bash script.

e.g. program.sh:

#!/bin/bash
python read_files.py

$Database_maindir/filename

.
.
.

How could I keep the string filename (the names of files in the directory) and write a loop in order to execute commands in bash script for each filename?

回答1:

The Python script in the question doesn't do anything that Bash cannot already do all by itself, and simpler and easier. Use simple native Bash instead:

shopt -s nullglob
for path in /home/testfiles/*; do
    if [[ -f "$path" ]]; then
        filename=$(basename "$path")
        echo "do something with $filename"
    fi
done

If the Python script does something more than what you wrote in the question, for example it does some complex computation and spits out filenames, which would be complicated to do in Bash, then you do have a legitimate use case to keep it. In that case, you can iterate over the lines in the output like this:

python read_files.py | while read -r filename; do
    echo "do something with $filename"
done

回答2:

Are you looking for something like this? =

for filename in $(python read_files.py); do 
    someCommand $filename
done

来源：https://stackoverflow.com/questions/53787850/python-read-the-filename-from-directory-use-the-string-in-bash-script

标签

python

bash