Python looping with try and except

不问归期 提交于 2021-02-08 05:01:54

问题


I am trying to write a program that reads numbers input by the user until the user types done. If the user types a non-number other than "done," I want to return an error message like "please enter a number number. When the user types "done", I want to calculate the total of the numbers, the number count and the average. I have tried to create a while loop with try and except to catch the non-numeric error other than done. That is part of the trick, a string entry is an error unless the string is "done." Here is the beginning of my code without any attempt to create a file that can be totaled, counted and maxed.

bank = 0
number = 0

while True:

    try:   
        number = int(raw_input("Enter an integer ( such as 49 or 3 or 16) \n"))
        bank = bank + number
        print 'You entered--- ', number, 'Your running total is ', bank    
    except:
        if number == 'done':
            print 'Done'
        else:
            if number == 'done':
                print 'Done'
            else:
                print 'Your entry was non-numberic.  Please enter a number.'    

bank = number + bank

When I run this and enter "done" I get the "else:" response and a new input line. I do not get the "Done" print from if number == "done"


回答1:


Answer written in python 3

The exception used is ValueError because the compiler catches this error as a result of the conversion done in line 7 so i just added the continue in line 19 to make it skip the error and go back to the start.

bank = 0
count = 0
while True:
    try:
        number = input('enter an integer:\n')
        if number != 'done':
            bank += int(number)
            print('you entered -- ', number, 'your total is ', bank)
            count += 1
        elif number == 'done':
            print('Done')
            print('you entered %d numbers' % count)
            print('Your total is %s' % bank)
            average = bank/count
            print('Your average is %.02f' % average)
            break
    except ValueError:
        print('oops!! that was not an integer')
        continue


来源:https://stackoverflow.com/questions/34569063/python-looping-with-try-and-except

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