How can I use PHP to setup an interactive SSH session?

巧了我就是萌 提交于 2021-02-07 08:37:45

问题


I'm trying to establish an interactive SSH connection to a remote server using PHP via the command line on Mac OS X 10.6. I'm currently using PHP's proc_open function to execute the following command:

ssh -t -t -p 22 user@server.com

This almost works. The -t -t options are supposed to force a pseudo terminal which they almost do. I am able to enter the SSH password and press enter. However, after pressing enter the terminal appears to simply hang. No output, no nothing - it's as if the SSH session has failed. I can't run commands or anything and have to kill the whole thing using Ctrl+C. I know the login is successful because I can execute a command like ssh -t -t -p 22 user@server.com "ls -la" and get the correct output.

I thought the problem must be related to the fact that I was using standard pipes in my proc_open call, so I replaced them with pty. I get the following error: "pty pseudo terminal not supported on this system..."

Does Mac OS X simply not support pty or pseudo terminals? (I'm pretty new at using all this shell terminology).

Here's the PHP code:

$descriptorspec = array(0 => array("pty"), 1 => array("pty"), 2 => array("pty"));  
$cwd = getcwd();  
$process = proc_open('ssh -t -t -p 22 user@server.com', $descriptorspec, $pipes, $cwd);  
if (is_resource($process))  
{  
    while (true)  
    {  
        echo(stream_get_contents($pipes[1]));  
        $status = proc_get_status($process);  
        if (! $status["running"])  
            break;  
    }  
} 

(Sorry - cannot for the life of me figure out SO's formatting instructions...)

What am I doing wrong? Why can't I use pty? Is this just impossible on Mac OS X? Thanks for your help!


回答1:


You should use public key authentication rather than trying to programmatically bypass interactive password authentication.

The password prompt is supposed to be used from a tty and I believe it was made intentionally difficult to use otherwise. Also the -t -t argument only takes effect once you are connected to the remote host. And I don't believe the PHP function proc_open() can run a command inside a virtual terminal.

To setup public key authentication:

# Generate keypair
ssh-keygen -t rsa

# Copy public key to server
scp ~/.ssh/id_rsa.pub example.com:.ssh/authorized_keys

# Now you shouldn't be prompted for a password when connecting to example.com
# from this host and user account.
ssh example.com

# Since the web server (and thus PHP) probably has its own user account...
# Copy the ~/.ssh/id_rsa file somewhere else
cp ~/.ssh/id_rsa /some_path/id_rsa

# Change ownership of the file to the web server account
chown www-data:www-data /some_path/id_rsa

# Fix the file permissions (ssh ignore the keyfile if it is world readable)
chown 600 /some_path/id_rsa

# Try connecting to the server through the web server account
su -c "ssh -i /some_path/id_rsa -o UserKnownHostsFile=/some_path/known_hosts example.com" www-data

# Add the host to the known hosts file when prompted


Alternately, you could use plink (part of PuTTY for Linux) instead of OpenSSH as it can take the password on the command line plink -pw password example.com. But doing so presents a security risk as anyone who runs ps aux on the server can see the password in the process list.

There is also a program called sshpass that takes the password from an environment variable or command argument and passes it to ssh.




回答2:


It looks like the problem is best solved using PHP's passthru() function. After alot more (rather painful) research I was able to issue a command through this function and could interact with the remote server through the terminal as if I had run ssh and svn export by hand (they both require passwords, therefore were good tests). What I'm going to have to do is construct a (potentially very long) string of commands separated by && and attach them to the end of the ssh command: ssh -t -t -p 22 hostname command1 && command2 ... The output will be sent to my terminal in Mac OS X even though the commands are being executed on the remote server. Looks like this is the solution I was looking for the whole time - pretty simple really! Thanks to everyone who helped me with this. I gave Alexandre the "green checkmark" because he was the only one who kept responding and was quite helpful in deducing the final answer to the problem. Thanks Alexandre!




回答3:


This is old, but for any googlers out there, here is an actual solution using proc_open:

Pty descriptors are available in PHP, but have to be configured during compilation (see this 10yr old bug report https://bugs.php.net/bug.php?id=33147)

But in python however, we don't have that problem. So instead of running the ssh command directly, run this python script:

import sys
import pty

args = " ".join(sys.argv[1:])
pty.spawn(['/usr/bin/ssh', args])

About pty.spawn from python docs:

Spawn a process, and connect its controlling terminal with the current process’s standard io. This is often used to baffle programs which insist on reading from the controlling terminal.




回答4:


Have you tried the PHP SSH2 extension?




回答5:


Have you tried phpseclib, a pure PHP SSH implementation?:

<?php
include('Net/SSH2.php');

$ssh = new Net_SSH2('www.domain.tld');
if (!$ssh->login('username', 'password')) {
    exit('Login Failed');
}

echo $ssh->read('username@username:~$');
$ssh->write("ls -la\n");
echo $ssh->read('username@username:~$');
?>



回答6:


I wrote a ssh client on php with ssh2 extension, you can take a look to the source code on the github page https://github.com/roke22/PHP-SSH2-Web-Client

Please send some feedback.



来源:https://stackoverflow.com/questions/4104236/how-can-i-use-php-to-setup-an-interactive-ssh-session

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