Printing list of numbers as an array from for loop Python

问题

With the code below, it prints the value 'phase' one by one. I am trying to print these values as an array outside of for loop.

import math

Period = 6.2

time1 = datafile1[:,0]
magnitude1 = datafile1[:,1]
for i in range(len(time1)):
   print(i,time1[i])
   floor = math.floor((time1[i]-time1[0])/Period)
   phase = ((time1[i]-time1[0])/Period)-floor 
   print (phase)

It is printing like this:

I would like it to print like this:

[0.002, 0.003, 0.004, 0.005]

回答1:

This would be the least modification requirement path to that result

result = []

time1 = datafile1[:,0]
magnitude1 = datafile1[:,1]
for i in range(len(time1)):
   result.append(i,time1[i])
   floor = math.floor((time1[i]-time1[0])/Period)
   phase = ((time1[i]-time1[0])/Period)-floor 
   result.append(phase)

print(result)

回答2:

Here I've made it so instead of printing your results, you append them to a list, then print out the full list.

import math

Period = 6.2

time1 = datafile1[:,0]
magnitude1 = datafile1[:,1]

my_list = []
for i in range(len(time1)):
   my_list.append(i,time1[i])
   floor = math.floor((time1[i]-time1[0])/Period)
   phase = ((time1[i]-time1[0])/Period)-floor 
   my_list.append(phase)

print(my_list)

回答3:

You can do

import math

Period = 6.2

time1 = datafile1[:,0]
magnitude1 = datafile1[:,1]
list_to_print = []
for i in range(len(time1)):
   print(i,time1[i])
   floor = math.floor((time1[i]-time1[0])/Period)
   phase = ((time1[i]-time1[0])/Period)-floor
   list_to_print.append(phase)
print (list_to_print)

来源：https://stackoverflow.com/questions/52509500/printing-list-of-numbers-as-an-array-from-for-loop-python

标签

python

arrays

for-loop