问题
How can a spline be created if only the points and the coefficients are known? I'm using scipy.interpolate.BSpline here, but am open to other standard packages as well. So basically I want to be able to give someone just those short arrays of coefficients for them to be able to recreate the fit to the data. See the failed red-dashed curve below.
import numpy as np
import matplotlib.pyplot as plt
from scipy.interpolate import BSpline, LSQUnivariateSpline
x = np.linspace(0, 10, 50) # x-data
y = np.exp(-(x-5)**2/4) # y-data
# define the knot positions
t = [1, 2, 4, 5, 6, 8, 9]
# get spline fit
s1 = LSQUnivariateSpline(x, y, t)
x2 = np.linspace(0, 10, 200) # new x-grid
y2 = s1(x2) # evaluate spline on that new grid
# FAILED: try to construct BSpline using the knots and coefficients
k = s1.get_knots()
c = s1.get_coeffs()
s2 = BSpline(t,c,2)
# plotting
plt.plot(x, y, label='original')
plt.plot(t, s1(t),'o', label='knots')
plt.plot(x2, y2, '--', label='spline 1')
plt.plot(x2, s2(x2), 'r:', label='spline 2')
plt.legend()
回答1:
The fine print under get_knots says:
Internally, the knot vector contains 2*k additional boundary knots.
That means, to get a usable knot array from get_knots, one should add k copies of the left boundary knot at the beginning of array, and k copies of the right boundary knot at the end. Here k is the degree of the spline, which is usually 3 (you asked for LSQUnivariateSpline of default degree, so that's 3). So:
kn = s1.get_knots()
kn = 3*[kn[0]] + list(kn) + 3*[kn[-1]]
c = s1.get_coeffs()
s2 = BSpline(kn, c, 3) # not "2" as in your sample; we are working with a cubic spline
Now, the spline s2 is the same as s1:
Equivalently, kn = 4*[x[0]] + t + 4*[x[-1]] would work: your t list contains only interior knots, so x[0] and x[-1] are added, and then each repeated k times more.
The mathematical reason for the repetition is that B-splines need some room to get built, due to their inductive definition which requires (k-1)-degree splines to exist around every interval in which we define the kth degree spline.
来源：https://stackoverflow.com/questions/52393145/create-bspline-from-knots-and-coefficients