问题
I have a cronjob that is the following:
*/10 * * * * root cd /some/directory && python3 FILE.py >> Output.txt 2>&1
if i run that command from a regular command line, it works fine. But when ran from cronjob, I get /bin/sh: python3: not found
But when I run echo $PATH it returns
/sbin:/bin:/usr/sbin:/usr/bin:/usr/syno/sbin:/usr/syno/bin:/usr/local/sbin:/usr/local/bin:/usr/local/python3/bin:/opt/bin
(Note that /usr/local/python3/bin is included in this directory
How do I fix this?
回答1:
It seems like cronjob has a different environment than your interactive shell. You could edit the cronjob to use an absolute path to call that python script. Or you can write a wrapper sh script to setup exactly the environment required by the python script and have cronjob execute that.
https://askubuntu.com/questions/23009/reasons-why-crontab-does-not-work
回答2:
Since the environnemnt variable are not used when crontab is running either you create them in your script... ...BUT YOU CAN ALSO check if /bin/python exits (or /sbin/python) and replace python with the one that exists :
*/10 * * * * root cd /some/directory && /bin/python3 FILE.py >> Output.txt 2>&1
or
*/10 * * * * root cd /some/directory && /sbin/python3 FILE.py >> Output.txt 2>&1
来源：https://stackoverflow.com/questions/34141380/cronjob-command-not-found