问题
I'm using sqlsrv_num_rows
in order to check if a user exists in the DB.
When i'm running the query in my DB i'm getting 1 result, but in my PHP I'm not getting anything (echo
doesn't print anything). Why is that?
$query = "SELECT TOP 1 id, tourOp FROM users WHERE (valid = 1) AND (email = '".trim($_POST['email'])."') AND (password = '".trim($_POST['password'])."')";
$stmt = sqlsrv_query( $conn, $query);
echo "num: ".sqlsrv_num_rows( $stmt );
if (!sqlsrv_num_rows( $stmt )) {
return (false);
} else {
}
Example query
SELECT TOP 1 id, name FROM users WHERE (valid = 1) AND (email = 'roi@some_email.com') AND (password = '8521')
I'm using PHP and MSSQL.
回答1:
Explanations:
- Function
sqlsrv_num_rows()
requires a client-side, static, or keyset cursor, and will returnfalse
if you use a forward cursor or a dynamic cursor (the default cursor is forward cursor). Executesqlsrv_query()
with additional$options
parameter and set the appropriate cursor type with"Scrollable" => SQLSRV_CURSOR_KEYSET
- Use parameterized statements. Function
sqlsrv_query()
does both statement preparation and statement execution and can be used to execute parameterized queries. - If you want to check if the result set has one or more rows, you may use
sqlsrv_has_rows()
.
Example, based on your code:
<?php
$query = "
SELECT TOP 1 id, tourOp
FROM users
WHERE (valid = 1) AND (email = ?) AND (password = ?)";
$params = array(trim($_POST['email']), trim($_POST['password']));
$options = array("Scrollable" => SQLSRV_CURSOR_KEYSET);
$stmt = sqlsrv_query( $conn, $query, $params, $options);
if ($exec === false){
echo print_r( sqlsrv_errors());
echo "<br>";
return (false);
}
$count = sqlsrv_num_rows($stmt);
if ($count === false) {
echo print_r( sqlsrv_errors());
echo "<br>";
return (false);
} else {
echo "num: ".$count;
}
?>
Notes:
Do not send user credentials in plain text.
来源:https://stackoverflow.com/questions/59037149/sql-select-doesnt-retrieve-results