问题
Say I have a list of tuples, like the following:
listo = [('a','1'),('b','0'),('c','2'),('d','0')]
If I want the lowest tuple, based on the second index of each tuple, I can customize the min function with a lambda function, like this:
min(listo, key=lambda x: x[1])
As it stands, this code would return:
In [31]: min(listo, key=lambda x: x[1])
Out[31]: ('b', '0')
But this only gives me one tuple, and only the first one it encounters at that. What if I wanted ALL the min tuples? So it returns something like:
In [31]: min(listo, key=lambda x: x[1])
Out[31]: [('b', '0'),('d','0')]
Any advice on how to accomplish this?
回答1:
You can do it by first searching one minimum value and then look for another ones based by the minimum value found.
listo = [('a','1'),('b','0'),('c','2'),('d','0')]
minValue = min(listo, key=lambda x: x[1])[1]
minValueList = [x for x in listo if x[1] == minValue]
Another approach could be making your own minimum function that uses some kind of list of minimum values but probably it would be much slower for bigger problems.
来源：https://stackoverflow.com/questions/17352387/can-i-return-a-list-of-all-min-tuples-using-pythons-min-function