UNIX C send() errno 14

问题

I have this code:

void caller()
{
    char buffer[20][20];
    int sd;
    ...
    send(sd, buffer[7], 5, 0);
}

Now I have this code:

void funct(int sd, char **buffer)
{
    send(sd, buffer[7], 5, 0);
}
void caller()
{
    char buffer[20][20];
    int sd;
    ...
    funct(sd, buffer);
}

---

To simplify suppose that instead of ... I have an initialization of socket UDP and connection with the server to use send instead of sendto. I don't understand why the second code generates on send an error and errno is set with value 14, but the first work perfectly.

来源：https://stackoverflow.com/questions/64035362/unix-c-send-errno-14