问题
Let's say I have a type:
let MyType =
    some info
    ...
but, it is commonly used in a list: MyType list
so I can define:
let MyTypeList =
    MyType list
is there a way to define a type augmentation on MyTypeList?
my practical case is that the type returns results of some work, it is handled in batches and I have some code that tell me if the whole batch is ok, if it is partially ok, or if everything went wrong. If I could add extensions to the list type, the syntax would be simpler.
 let a : MyTypeList = ...
 if a.IsAllOk() then ...
but I can't find how to make this with a list.
回答1:
There are two different ways of definining type extensions in F#. One option is via an F# type augmentation and the other is (C#-compatible) extension method.
The extension method approach lets you define extensions for a specific type instantiation, including for example list<MyType>:
type MyType = { N : int }
type MyTypeList = int list
[<System.Runtime.CompilerServices.Extension()>]
type MyTypeListExtensions() = 
  [<System.Runtime.CompilerServices.Extension()>]
  static member AllOk(l:MyTypeList) = false
let foo (a:MyTypeList) = 
  a.AllOk()
来源:https://stackoverflow.com/questions/62703688/type-extension-on-a-list-in-f