镜像点思路
具体见这篇博客
i的信息存在i'里在2操作时就不会有影响

#include<bits/stdc++.h>
#define N 200003
using namespace std;
int read()
{
int x=0,f=1;char s=getchar();
while(s<'0'||s>'9'){if(s=='-')f=-1;s=getchar();}
while(s>='0'&&s<='9'){x=x*10+s-'0';s=getchar();}
return x*f;
}
int fa[N],num[N],sum[N];
void init(int n)
{
for(int i=1;i<=n;++i)
{
fa[i]=i+n;fa[i+n]=i+n;
sum[i+n]=i;num[i+n]=1;
}
}
int get(int x)
{
if(fa[x]==x)return x;
return fa[x]=get(fa[x]);
}
int main()
{
int n,m;
while(scanf("%d%d",&n,&m)!=EOF)
{
init(n);
for(int i=1;i<=m;++i)
{
int op=read();
if(op==1)
{
int p=read(),q=read();
int f1=get(p),f2=get(q);
if(f1==f2)continue;
fa[f1]=f2;
sum[f2]+=sum[f1];
num[f2]+=num[f1];
}
else if(op==2)
{
int p=read(),q=read();
int f1=get(p),f2=get(q);
if(f1==f2)continue;
fa[p]=f2;
sum[f1]-=p;num[f1]--;
sum[f2]+=p;num[f2]++;
}
else
{
int p=read();
int f=get(p);
printf("%d %d\n",num[f],sum[f]);
}
}
}
}
