Comparing Python, Numpy, Numba and C++ for matrix multiplication

问题

In a program I am working on, I need to multiply two matrices repeatedly. Because of the size of one of the matrices, this operation takes some time and I wanted to see which method would be the most efficient. The matrices have dimensions (m x n)*(n x p) where m = n = 3 and 10^5 < p < 10^6.

With the exception of Numpy, which I assume works with an optimized algorithm, every test consists of a simple implementation of the matrix multiplication:

Below are my various implementations:

Python

def dot_py(A,B):
    m, n = A.shape
    p = B.shape[1]

    C = np.zeros((m,p))

    for i in range(0,m):
        for j in range(0,p):
            for k in range(0,n):
                C[i,j] += A[i,k]*B[k,j] 
    return C

Numpy

def dot_np(A,B):
    C = np.dot(A,B)
    return C

Numba

The code is the same as the Python one, but it is compiled just in time before being used:

dot_nb = nb.jit(nb.float64[:,:](nb.float64[:,:], nb.float64[:,:]), nopython = True)(dot_py)

So far, each method call has been timed using the timeit module 10 times. The best result is kept. The matrices are created using np.random.rand(n,m).

C++

mat2 dot(const mat2& m1, const mat2& m2)
{
    int m = m1.rows_;
    int n = m1.cols_;
    int p = m2.cols_;

    mat2 m3(m,p);

    for (int row = 0; row < m; row++) {
        for (int col = 0; col < p; col++) {
            for (int k = 0; k < n; k++) {
                m3.data_[p*row + col] += m1.data_[n*row + k]*m2.data_[p*k + col];
            }
        }
    }

    return m3;
}

Here, mat2 is a custom class that I defined and dot(const mat2& m1, const mat2& m2) is a friend function to this class. It is timed using QPF and QPC from Windows.h and the program is compiled using MinGW with the g++ command. Again, the best time obtained from 10 executions is kept.

Results

As expected, the simple Python code is slower but it still beats Numpy for very small matrices. Numba turns out to be about 30% faster than Numpy for the largest cases.

I am surprised with the C++ results, where the multiplication takes almost an order of magnitude more time than with Numba. In fact, I expected these to take a similar amount of time.

This leads to my main question: Is this normal and if not, why is C++ slower that Numba? I just started learning C++ so I might be doing something wrong. If so, what would be my mistake, or what could I do to improve the efficiency of my code (other than choosing a better algorithm) ?

EDIT 1

Here is the header of the mat2 class.

#ifndef MAT2_H
#define MAT2_H

#include <iostream>

class mat2
{
private:
    int rows_, cols_;
    float* data_;

public: 
    mat2() {}                                   // (default) constructor
    mat2(int rows, int cols, float value = 0);  // constructor
    mat2(const mat2& other);                    // copy constructor
    ~mat2();                                    // destructor

    // Operators
    mat2& operator=(mat2 other);                // assignment operator

    float operator()(int row, int col) const;
    float& operator() (int row, int col);

    mat2 operator*(const mat2& other);

    // Operations
    friend mat2 dot(const mat2& m1, const mat2& m2);

    // Other
    friend void swap(mat2& first, mat2& second);
    friend std::ostream& operator<<(std::ostream& os, const mat2& M);
};

#endif

Edit 2

As many suggested, using the optimization flag was the missing element to match Numba. Below are the new curves compared to the previous ones. The curve tagged v2 was obtained by switching the two inner loops and shows another 30% to 50% improvement.

回答1:

Definitely use -O3 for optimization. This turns vectorizations on, which should significantly speed your code up.

Numba is supposed to do that already.

回答2:

What I would recommend

If you want maximum efficiency, you should use a dedicated linear algebra library, the classic of which is BLAS/LAPACK libraries. There are a number of implementations, eg. Intel MKL. What you write is NOT going to outpeform hyper-optimized libraries.

Matrix matrix multiply is going to be the dgemm routine: d stands for double, ge for general, and mm for matrix matrix multiply. If your problem has additional structure, a more specific function may be called for additional speedup.

Note that Numpy dot ALREADY calls dgemm! You're probably not going to do better.

Why your c++ is slow

Your classic, intuitive algorithm for matrix-matrix multiplication turns out to be slow compared to what's possible. Writing code that takes advantage of how processors cache etc... yields important performance gains. The point is, tons of smart people have devoted their lives to making matrix matrix multiply extremely fast, and you should use their work and not reinvent the wheel.

回答3:

In your current implementation most likely compiler is unable to auto vectorize the most inner loop because its size is 3. Also m2 is accessed in a "jumpy" way. Swapping loops so that iterating over p is in the most inner loop will make it work faster (col will not make "jumpy" data access) and compiler should be able to do better job (autovectorize).

for (int row = 0; row < m; row++) {
    for (int k = 0; k < n; k++) {
        for (int col = 0; col < p; col++) {
            m3.data_[p*row + col] += m1.data_[n*row + k] * m2.data_[p*k + col];
        }
    }
}

On my machine the original C++ implementation for p=10^6 elements build with g++ dot.cpp -std=c++11 -O3 -o dot flags takes 12ms and above implementation with swapped loops takes 7ms.

来源：https://stackoverflow.com/questions/36526708/comparing-python-numpy-numba-and-c-for-matrix-multiplication

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python

c++

numpy

optimization

numba