DataGridView set column cell Combobox

Question

I have tables like that in Datagridview:

 Name   Money
 -------------
 Hi      100   //here Combobox with member {10,30,80,100} to choose
 Ki      30    //here Combobox with member {10,30,80,100} to choose

I want to change Column "Money" Value from combobox

I tried with this but dont know further:

DataTable dt = new DataTable();
dt.Columns.Add("Name", typeof(String));
dt.Columns.Add("Money", typeof(String));
dt.Rows.Add(new object[] { "Hi", 100});
dt.Rows.Add(new object[] { "Ki", 30});

DataGridViewComboBoxColumn column = new DataGridViewComboBoxColumn();
var list11 = new List<string>() { "10", "30", "80", "100" };
column.DataSource = list11;
column.ValueMember = "Money";
dataGridView1.Columns.Add(column); 

Answer 1

Try this

dataGridView1.AutoGenerateColumns = false;

DataTable dt = new DataTable();
dt.Columns.Add("Name", typeof(String));
dt.Columns.Add("Money", typeof(String));
dt.Rows.Add(new object[] { "Hi", 100 });
dt.Rows.Add(new object[] { "Ki", 30 });

DataGridViewComboBoxColumn money = new DataGridViewComboBoxColumn();
var list11 = new List<string>() { "10", "30", "80", "100" };
money.DataSource = list11;
money.HeaderText = "Money";
money.DataPropertyName = "Money";

DataGridViewTextBoxColumn name = new DataGridViewTextBoxColumn();
name.HeaderText = "Name";
name.DataPropertyName = "Name";

dataGridView1.DataSource = dt;
dataGridView1.Columns.AddRange(name, money);

Just use DataPropertyName instead of ValueMember

Answer 2

You were almost done.

There are only two minor issues:

1. In your table you are adding to rows "Money" value as integers, while in your column they are defined as string
2. First add your table ad DataGridView DataSource, and then set column DataPropertyName

Full code below:

var table = new DataTable();
table.Columns.Add("Name", typeof(string));
table.Columns.Add("Money", typeof(string));
table.Rows.Add("Hi", "100");
table.Rows.Add("Ki", "30");

var column = new DataGridViewComboBoxColumn();
column.DataSource = new List<string>() { "10", "30", "80", "100" };            

dataGridView1.Columns.Add(column);
dataGridView1.DataSource = table;

Answer 3

You could try the following:

DataGridViewComboBoxColumn column = new DataGridViewComboBoxColumn();
column.Name = "Money";
column.DataSource = new string[] { "10", "30", "80", "100" };
dataGridView1.Columns.Add(column);

for (int row = 0; row < dataGridView1.Columns.Count; row++)
{
   DataGridViewComboBoxCell cell = 
       (DataGridViewComboBoxCell)(dataGridView1.Rows[row].Cells["Money"]);
   cell.DataSource = new string[] { "80", "100" };
}

Or this:

foreach (DataGridViewRow row in dataGridView1.Rows)
{
    DataGridViewComboBoxCell cell = (DataGridViewComboBoxCell)(row.Cells["Money"]);
    cell.DataSource = new string[] { "10", "30" };
}

Answer 4

You can replace with

dt.Columns.Add("Money", typeof(List<string>));

Answer 5

Note the index of your ComboBox column when you set up the grid in the designer. In this example it is 1. The Money column is index 1. The grid already has a member that is a DataGridViewComboBoxColumn. When you initialize the form that contains the control get it and initialize it. Like this:

DataGridViewComboBoxColumn cbc = (DataGridViewComboBoxColumn)dataGridView1.Columns[1];
cbc.Items.Add("10");
cbc.Items.Add("30");
cbc.Items.Add("80");
cbc.Items.Add("100");

When you populate the grid, insert text values into that cell. When the user clicks on the cell the droplist will appear and they'll be able to change the value.

Really, if all you want to do is just have a drop list with those values, you can do it right from within the designer by modifying the Items collection.

Answer 6

I know it's late but Try this:

            DataTable dt = new DataTable();
            dt.Columns.Add("Name", typeof(String));
            dt.Columns.Add("Money", typeof(String));
            dt.Rows.Add(new object[] { "Hi", 100 });
            dt.Rows.Add(new object[] { "Ki", 30 });

            DataTable dt2 = new DataTable();
            dt2.Columns.Add("Money", typeof(String));
            dt2.Columns.Add("Meaning", typeof(String));
            dt2.Rows.Add(new object[] { "30" ,"Name 1" });
            dt2.Rows.Add(new object[] { "100", "Name 2" });
            dt2.Rows.Add(new object[] { "80", "Name 3" });
            dt2.Rows.Add(new object[] { "90", "Name4" });

            DataGridViewComboBoxColumn money = new DataGridViewComboBoxColumn();

            money.DataSource = dt2;
            money.HeaderText = "Money";
            money.DataPropertyName = "Money";
            money.DisplayMember = "Meaning";
            money.ValueMember = "Money";

            DataGridViewTextBoxColumn name = new DataGridViewTextBoxColumn();
            name.HeaderText = "Name";
            name.DataPropertyName = "Name";

            DGV.Columns.Add(money);
            DGV.Columns.Add(name);
            DGV.DataSource = dt;

Answer 7

((DataGridViewComboBoxColumn)dgvFacturas.Columns["estatus"]).DataSource = estatustemp.ToList();
((DataGridViewComboBoxColumn)dgvFacturas.Columns["estatus"]).ValueMember = "Key";
((DataGridViewComboBoxColumn)dgvFacturas.Columns["estatus"]).DisplayMember = "Value";