How can I easily get a Scala case class's name?

问题

Given:

case class FirstCC {
  def name: String = ... // something that will give "FirstCC"
}
case class SecondCC extends FirstCC
val one = FirstCC()
val two = SecondCC()

How can I get "FirstCC" from one.name and "SecondCC" from two.name?

回答1:

def name = this.getClass.getName

Or if you want only the name without the package:

def name = this.getClass.getSimpleName

See the documentation of java.lang.Class for more information.

回答2:

You can use the property productPrefix of the case class:

case class FirstCC {
  def name = productPrefix
}
case class SecondCC extends FirstCC
val one = FirstCC()
val two = SecondCC()

one.name
two.name

N.B. If you pass to scala 2.8 extending a case class have been deprecated, and you have to not forget the left and right parent ()

回答3:

class Example {
  private def className[A](a: A)(implicit m: Manifest[A]) = m.toString
  override def toString = className(this)
}

回答4:

def name = this.getClass.getName

回答5:

Here is a Scala function that generates a human-readable string from any type, recursing on type parameters:

https://gist.github.com/erikerlandson/78d8c33419055b98d701

import scala.reflect.runtime.universe._

object TypeString {

  // return a human-readable type string for type argument 'T'
  // typeString[Int] returns "Int"
  def typeString[T :TypeTag]: String = {
    def work(t: Type): String = {
      t match { case TypeRef(pre, sym, args) =>
        val ss = sym.toString.stripPrefix("trait ").stripPrefix("class ").stripPrefix("type ")
        val as = args.map(work)
        if (ss.startsWith("Function")) {
          val arity = args.length - 1
          "(" + (as.take(arity).mkString(",")) + ")" + "=>" + as.drop(arity).head
        } else {
          if (args.length <= 0) ss else (ss + "[" + as.mkString(",") + "]")
        }
      }
    }
    work(typeOf[T])
  }

  // get the type string of an argument:
  // typeString(2) returns "Int"
  def typeString[T :TypeTag](x: T): String = typeString[T]
}

回答6:

def name = getClass.getSimpleName.split('$').head

This will remove the $1 appearing at the end on some classes.

来源：https://stackoverflow.com/questions/2656364/how-can-i-easily-get-a-scala-case-classs-name

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