Reading and printing an integer in mips

坚强是说给别人听的谎言 提交于 2020-07-14 22:29:09

问题


My program is suppose to read an integer and print it back to the user but every time it just prints 268501230 no matter what is entered. Any help would be appreciated.

.data
prompt2: .asciiz "Please enter value: "
array1: .space 40
array2: .space 40
buffer: .space 4
.text

main: 

#Prints the prompt2 string
li $v0, 4
la $a0, prompt2 
syscall 

#reads one integer from user and saves in t0
li $v0, 5
la $t0, buffer
syscall

li $v0, 1       
li $t0, 5       # $integer to print
syscall         

exitProgram:    li $v0, 10  # system call to
    syscall         # terminate program

回答1:


This is how I will write a program to get an integer input and to print it out

.data

     text:  .asciiz "Enter a number: "

.text

 main:
    # Printing out the text
    li $v0, 4
    la $a0, text
    syscall

    # Getting user input
    li $v0, 5
    syscall

    # Moving the integer input to another register
    move $t0, $v0

    # Printing out the number
    li $v0, 1
    move $a0, $t0
    syscall

    # End Program
    li $v0, 10
    syscall



回答2:


#reads one integer from user and saves in t0
li $v0, 5
la $t0, buffer
syscall

That's not how syscall 5 works. The integer is returned in $v0, so the code ought to be something like:

li $v0,5
syscall
move $t0,$v0

li $v0, 1       
li $t0, 5       # $integer to print
syscall 

You're using the wrong register here as well. The integer to print should go into $a0, not $t0.

Here's a list of syscalls and the registers they use.



来源:https://stackoverflow.com/questions/19748054/reading-and-printing-an-integer-in-mips

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