`object.__setattr__(self, …, …)` instead of `setattr(self, …, …)`?

问题

Following is the __init__ method of the Local class from the werkzeug library:

def __init__(self):
    object.__setattr__(self, '__storage__', {})
    object.__setattr__(self, '__ident_func__', get_ident)

I don't understand two things about this code:

Why did they write

object.__setattr__(self, '__storage__', {})

instead of simply

`setattr(self, '__storage__', {})`

Why did they even use __setattr__ if the could simply write
```
self.__storage__ = {}
```

回答1:

This ensures that the default Python definition of __setattr__ is used. It's generally used if the class has overridden __setattr__ to perform non-standard behaviour, but you still wish to access the original __setattr__ behaviour.

In the case of werkzeug, if you look at the Local class you'll see __setattr__ is defined like this:

def __setattr__(self, name, value):
    ident = self.__ident_func__()
    storage = self.__storage__
    try:
        storage[ident][name] = value
    except KeyError:
        storage[ident] = {name: value}

Instead of setting attributes in the dictionary of the object, it sets them in the __storage__ dictionary that was initialized previously. In order to set the __storage__ attribute at all (so that it may be accessed like self.__storage__ later), the original definition of __setattr__ from object must be used, which is why the awkward notation is used in the constructor.

回答2:

They want to explicitly use the base object.__setattr__ implementation instead of a possibly overridden method instance method somewhere else in the inheritance chain. Local implements its own __setattr__ so this avoids that.

回答3:

Because the same class defines __setattr__ and this needs to bypass that, since the first line says self.__ident_func__() which wouldn't work yet.

来源：https://stackoverflow.com/questions/33041518/object-setattr-self-instead-of-setattrself

标签

python

class

methods