How to use Postgres jsonb '?' operator in Laravel with index support?

问题

I'm trying to use the jsonb exists operator '?' in Laravel's query builder, and have it use an index, but I've run into some issues.

Sample query

DB::table('table_name')->whereRaw("jsonb_column ? 'key'")->get();

Sample Index

CREATE INDEX ON table_name USING GIN(jsonb_column jsonb_ops)

The main issue seems to be that '?' is reserved for parameter replacement, so this query returns a syntax error. I've found a couple ways around this, but each are incomplete solutions.

1. use '??' (a way to escape the ?) ->whereRaw("jsonb_column ?? 'key'")

   • doesn't work with querybuilder. returns SQLSTATE[42883]: Undefined function: 7 ERROR: operator does not exist: jsonb ?? unknown
   • works with raw queries, e.g. DB::select("SELECT * FROM table_name WHERE jsonb_column ?? 'key'"), but I need it to work with the query builder.

2. use a named function / create an alias for the operator

   • '?' translates to the function - jsonb_exists(jsonb, text)
     • ->whereRaw("jsonb_exists(jsonb_column, 'key')")
   • CREATE OPERATOR @-> ( PROCEDURE = jsonb_exists, LEFTARG = jsonb, RIGHTARG = text );
     • ->whereRaw("jsonb_column @-> 'key'")
   • these solutions both "work"... but they don't use indexes

Right now I'm researching CREATE OPERATOR CLASS, as a way to get my custom operator to use gin indexing, but it's a bit over my head. If anybody can give me some tips on how to accomplish this or, even better, some simpler solution, it'd be a huge help.

edit

• using php 7.3

回答1:

PHP 7.4 allows you to escape the placeholder with ??: https://wiki.php.net/rfc/pdo_escape_placeholders

DB::table('table_name')->whereRaw('jsonb_column ?? ?', ['key'])->get();

来源：https://stackoverflow.com/questions/60310077/how-to-use-postgres-jsonb-operator-in-laravel-with-index-support