Javascript compare numbers as strings

问题

I wish to compare two strings in javascript. I am using localeCompare method but the output is not as expected

116457 < 3085
false

"116457" < "3085"
true

"116457".localeCompare("3085")
-1

Output in second and third case is not as expected.

I know it sorts in Lexicographical order but still I am having trouble understanding why is it so and how should I overcome this.

Any help would be appreciated.

回答1:

If you want to compare them without converting them to numbers, you can set numeric: true in the options parameter

console.log(
  "116457".localeCompare("3085", undefined, { numeric: true })
)
console.log(
  "116457".localeCompare("3085")
)

回答2:

If 116457 were a word, it would come before 3085 in a dictionary.

Consider a dictionary with

• "applicative" (a long word starting with "a", c.f. a long digit string starting with "1")
• "copy" (a short word starting with "c", c.f. a shorter digit string starting with "3").

来源：https://stackoverflow.com/questions/56988641/javascript-compare-numbers-as-strings