How does derived class arguments work in Python?

问题

I am having difficulty understanding one thing in Python.I have been coding in Python from a very long time but there's is something that just struck me today which i struggle to understand

So the situation goes like this

I have a mixin and a view

class Mixin:
    def get_session(self,request,*args,**kwargs):
        print(self) #should be the instance passed
        print(request) #should be the request object passed but it's also an instance

class View:
     def get(self,request,*args,**kwargs):
         self.get_session(self,request,*args,*kwargs)
         pass

Why is the request argument the instance of the Class View, It should be request.Please help me clarify these concepts.

回答1:

You're passing self explicitly as the first argument of get_session. That means it goes into the request parameter.

self.get_session(self,request,*args,*kwargs)
  ^               ^        ^^^^^^^^^^
(self)        (request)    (the rest)

I think you mean:

self.get_session(request, *args, **kwargs)

来源：https://stackoverflow.com/questions/60929560/how-does-derived-class-arguments-work-in-python