How to call a Celery shared_task?

问题

I'm trying to use stream_framework in my application (NOT Django) but I'm having a problem calling the stream_framework shared tasks. Celery seems to find the tasks:

-------------- celery@M3800 v3.1.25 (Cipater)
---- **** ----- 
--- * ***  * -- Linux-4.15.0-34-generic-x86_64-with-Ubuntu-18.04-bionic
-- * - **** --- 
- ** ---------- [config]
- ** ---------- .> app:         task:0x7f8d22176dd8
- ** ---------- .> transport:   redis://localhost:6379/0
- ** ---------- .> results:     redis://localhost:6379/0
- *** --- * --- .> concurrency: 8 (prefork)
-- ******* ---- 
--- ***** ----- [queues]
 -------------- .> celery           exchange=celery(direct) key=celery


[tasks]
  . formshare.processes.feeds.tasks.test_shared_task
  . stream_framework.tasks.fanout_operation
  . stream_framework.tasks.fanout_operation_hi_priority
  . stream_framework.tasks.fanout_operation_low_priority
  . stream_framework.tasks.follow_many
  . stream_framework.tasks.unfollow_many

[2018-09-17 10:06:28,240: INFO/MainProcess] Connected to redis://localhost:6379/0
[2018-09-17 10:06:28,246: INFO/MainProcess] mingle: searching for neighbors
[2018-09-17 10:06:29,251: INFO/MainProcess] mingle: all alone

I run celery with:

celery -A formshare.processes.feeds.celery_app worker --loglevel=info

My celery_app has:

from celery import Celery

celeryApp = Celery('task', broker='redis://localhost:6379/0', backend='redis://localhost:6379/0', include='formshare.processes.feeds.tasks')

The problem is that delay() does not run the shared task. I also created a shared task within my application but when I call delay() the task is also not called. I guess I need to register them as callable from my application? I don't seem to find any information online.

I also tried to auto discover the tasks but I got the same problem:

celeryApp.autodiscover_tasks(['stream_framework', 'formshare.processes.feeds'],force=True)

Any idea is highly appreciated.

回答1:

Shared task are a specific thing used to actually share tasks between different applications (mainly Django apps I think, but I used them in flask for example).

We had the same issue and to get it to work we set

 celery_app.set_default()

On the celery instantiation

Otherwise another way of getting things right is to actually call the task via the app itself, so something around these lines

from celery import current_app
.
.
.
current_app.tasks['my.tasks.to.exec'].delay(something)

This always works as, given it s a shared task and therefore is not bound to any app when you import it, in this case it belongs to the app configured as the "current_app"

来源：https://stackoverflow.com/questions/52372117/how-to-call-a-celery-shared-task

标签

celery

celery-task

stream-framework