求数列的和

思路:利用sqrt函数计算根号,再依次累计相加
代码:
#include<iostream>
#include<math.h>
using namespace std;
int main()
{
double m, n;
double num, sum;
while (cin >> m >> n)
{
sum = 0;
num = m;
int i;
for (i = 0; i < n; i++)
{
sum += num;
num = sqrt(num);
}
printf("%0.2lf\n", sum);
}
system("pause");
return 0;
}
来源:https://www.cnblogs.com/pcdl/p/12250509.html