Run shell_plus through PyCharm?

问题

Is there a way for me to configure PyCharm to run shell_plus instead of the default shell?

I've tried putting the text of the manage command in the 'Starting script' but then I get the folloiwing django_manage_shell.run("/Users/cmason/counsyl/code/website/counsyl/product") import os import sys

if __name__ == "__main__":
    os.environ.setdefault("DJANGO_SETTINGS_MODULE", "settings")

    # The new Django 1.4 default manage.py wants "from django..." before
    # importing settings, but we usually tinker with sys.path in
    # settings_local.py, which is called from settings.py. Importing
    # settings.py works but does mean some double importing. Luckily that
    # module does very little work.
    import settings
    # appease pyflakes; don't ever do this in
    # non-super-meta-namespace-trickery code
    settings

    from django.core.management import execute_from_command_line

    execute_from_command_line("shellplus")

and it hasn't really run shell_plus.

It seems like the 'Starting script' happens in addition to rather than instead of the default.

Shell_plus automatically imports all Django model classes, among other things.

回答1:

I got the model objects auto-loading by hooking into the shell_plus code. I appended this to the default startup script in Preferences > Build, Execution, Deployment > Console > Django Console:

from django_extensions.management import shells
from django.core.management.color import color_style
imported_items = shells.import_objects({}, color_style())
for k, v in imported_items.items():
    globals()[k] = v

This was on PyCharm 2018.3.3 Pro

For completeness, this was the full content of starting script:

import sys; print('Python %s on %s' % (sys.version, sys.platform))
import django; print('Django %s' % django.get_version())
sys.path.extend([WORKING_DIR_AND_PYTHON_PATHS])
if 'setup' in dir(django): django.setup()
import django_manage_shell; django_manage_shell.run(PROJECT_ROOT)

from django_extensions.management import shells
from django.core.management.color import color_style
imported_items = shells.import_objects({}, color_style())
for k, v in imported_items.items():
    globals()[k] = v

回答2:

I've been looking for a solution to the same problem, and I ended up here. I tried solutions proposed by others, but none of those appeared to solve this issue. So I decided to find another solution. This is what I came up with:

The code block below is the original Django Console starting script of PyCharm 2019.2:

import sys, django
print('Python %s on %s' % (sys.version, sys.platform))
print('Django %s' % django.get_version())
sys.path.extend([WORKING_DIR_AND_PYTHON_PATHS])
if 'setup' in dir(django):
    django.setup()
import django_manage_shell
django_manage_shell.run(PROJECT_ROOT)

Installing IPython and changing the last two lines as below gets it done in the most proper way:

from IPython.core.getipython import get_ipython
ipython = get_ipython()
from django_extensions.management.notebook_extension import load_ipython_extension
load_ipython_extension(ipython)

To make it work: open PyCharm settings (CTRL+S) and head to Django Console section. Then make changes in Starting script window and apply. Finally, start the new Python Console instance.

回答3:

This isn't a complete answer, but I found this script that at least loads up all the app models. Put this in Settings > Console > Django Console > Starting script:

import sys
import logging
logging.basicConfig(format="%(levelname)-8s %(asctime)s %(name)s %(message)s", datefmt='%m/%d/%y %H:%M:%S', stream=sys.stdout )
log = logging.getLogger("root")

from django.db.models import get_models
from django.conf import settings
from django.core.exceptions import ObjectDoesNotExist, MultipleObjectsReturned

logging.config.dictConfig(settings.LOGGING)
log.debug("Logging has been initialized at DEBUG")
log.setLevel( logging.DEBUG)
log.disabled = False

for _class in get_models():
    if _class.__name__.startswith("Historical"): continue
    log.debug("Registering model {}".format(_class.__name__))
    globals()[_class.__name__] = _class

def debug_sql():
    from debug_toolbar.management.commands import debugsqlshell
    return

I also submitted this a feature request to JetBrains.

回答4:

In Django 1.7, following script can be used as a workaround with PyCharm 3.4:

File -> Settings -> Console -> Django Console and manage.py options

In Starting script, put:

import sys
import django
django.setup()

from django.db.models import get_models

for _class in get_models():
    globals()[_class.__name__] = _class

回答5:

As django.db.models.get_models no longer exists, here's an updated version that will accomplish the same as Christopher Mason's version.

import sys; print('Python %s on %s' % (sys.version, sys.platform))
import django; print('Django %s' % django.get_version())
import logging
logging.basicConfig(format="%(levelname)-8s %(asctime)s %(name)s %(message)s", datefmt='%m/%d/%y %H:%M:%S', stream=sys.stdout )
log = logging.getLogger("root")

from django.apps import apps
from django.conf import settings  
from django.core.exceptions import ObjectDoesNotExist, MultipleObjectsReturned

logging.config.dictConfig(settings.LOGGING)
log.debug("Logging has been initialized at DEBUG")
log.setLevel( logging.DEBUG)
log.disabled = False

for _configs in apps.get_app_configs():
    for _class in _configs.get_models():
        if _class.__name__.startswith("Historical"): continue
        log.debug("Registering model {}".format(_class.__name__))
        globals()[_class.__name__] = apps.get_model(_configs.label, _class.__name__)

def debug_sql():
    from debug_toolbar.management.commands import debugsqlshell
    return

来源：https://stackoverflow.com/questions/19868449/run-shell-plus-through-pycharm

标签

python

django

pycharm