How to call through a member function pointer?

问题

I\'m trying to do some testing with member function pointer. What is wrong with this code? The bigCat.*pcat(); statement doesn\'t compile.

class cat {
public:
   void walk() {
      printf(\"cat is walking \\n\");
   }
};

int main(){
   cat bigCat;
   void (cat::*pcat)();
   pcat = &cat::walk;
   bigCat.*pcat();
}

回答1:

More parentheses are required:

(bigCat.*pcat)();
^            ^

The function call (()) has higher precedence than the pointer-to-member binding operator (.*). The unary operators have higher precedence than the binary operators.

来源：https://stackoverflow.com/questions/12189057/how-to-call-through-a-member-function-pointer