heatmap-like plot, but for categorical variables in seaborn

问题

Same question as heatmap-like plot, but for categorical variables but using python and seaborn instead of R:

Imagine I have the following dataframe:

df = pd.DataFrame({"John":"No Yes Maybe".split(),
                   "Elly":"Yes Yes Yes".split(),
                   "George":"No Maybe No".split()},
                   index="Mon Tue Wed".split())

Now I would like to plot a heatmap and color each cell by its corresponding value. That is "Yes", "No", "Maybe", for instance becomes "Green", "Gray", "Yellow". The legend should have those three colors and the corresponding values.

I solved this problem myself in the following manner. I can't seem to pass a categorical color map to seaborn's heatmap, so instead I replace all text by numbers and reconstruct the color map used by seaborn internally afterwards i.e.:

import pandas as pd
import seaborn as sns
import matplotlib.pyplot as plt
import numpy as np
import matplotlib.patches as mpatches

# create dictionary with value to integer mappings
value_to_int = {value: i for i, value in enumerate(sorted(pd.unique(df.values.ravel())))}

f, ax = plt.subplots()
hm = sns.heatmap(df.replace(value_to_int).T, cmap="Pastel2", ax=ax, cbar=False)
# add legend
box = ax.get_position()
ax.set_position([box.x0, box.y0, box.width * 0.7, box.height])
legend_ax = f.add_axes([.7, .5, 1, .1])
legend_ax.axis('off')
# reconstruct color map
colors = plt.cm.Pastel2(np.linspace(0, 1, len(value_to_int)))
# add color map to legend
patches = [mpatches.Patch(facecolor=c, edgecolor=c) for c in colors]
legend = legend_ax.legend(patches,
    sorted(value_to_int.keys()),
    handlelength=0.8, loc='lower left')
for t in legend.get_texts():
    t.set_ha("left")

My question: is there a more succinct way of making this heatmap? If not, this might be a feature worth implementing in which case I'll post it on the seaborn issue tracker.

回答1:

You can use a discrete colormap and modify the colorbar, instead of using a legend.

value_to_int = {j:i for i,j in enumerate(pd.unique(df.values.ravel()))} # like you did
n = len(value_to_int)     
# discrete colormap (n samples from a given cmap)
cmap = sns.color_palette("Pastel2", n) 
ax = sns.heatmap(df.replace(value_to_int), cmap=cmap) 
# modify colorbar:
colorbar = ax.collections[0].colorbar 
r = colorbar.vmax - colorbar.vmin 
colorbar.set_ticks([colorbar.vmin + r / n * (0.5 + i) for i in range(n)])
colorbar.set_ticklabels(list(value_to_int.keys()))                                          
plt.show()

The colorbar part is adapted from this answer

HTH

回答2:

I would probably use bokeh for this purpose as it has categorical heatmaps built in. Y-axis labels are written horizontally too, which is more readable.

http://docs.bokeh.org/en/0.11.1/docs/gallery/heatmap_chart.html

来源：https://stackoverflow.com/questions/36227475/heatmap-like-plot-but-for-categorical-variables-in-seaborn

标签

python

matplotlib

seaborn