问题
puts bool ? "true" : "false"
is proper, but
bool ? puts "true" : puts "false"
is not. Can somebody explain to me why this is?
Side note:
bool ? ( puts "true" ) : ( puts "false" )
works fine as well.
回答1:
When you don't put the parentheses on a method call, Ruby assumes you want everything to the end of the line to be the arguments. That is to say, these calls are equivalent (and invalid):
bool ? puts "true" : puts "false"
bool ? puts("true" : puts "false")
来源：https://stackoverflow.com/questions/16629567/ruby-ternary-operator-structure