javac code elimination capabilities

问题

I'm having a hard time finding information about javac's code elimination capabilities:

I read that if you have something like the following, the if-statement will be eliminated:

static final boolean DEBUG = false;

if (DEBUG) System.out.println("Hello World!"); // will be removed

But how about this, for example:

static final int VALUE = 3;

if (VALUE > 9) System.out.println("VALUE > 9 ???"); // will this be removed?

Or this:

static final SomeEnum VALUE = SomeEnum.FOO;

if (VALUE==SomeEnum.BAR) System.out.println("Bar???"); // will this be removed?

Since it's very difficult/impossible to analyze a program to find all dead code (probably similar to the halting problem), I would imagine that there are only a few well-defined constructs (like the first example above), which javac will recognize and remove reliably. Is there a comprehensive list of these constructs?

回答1:

assylias seems to have found the answer (let me just put it all together):

Chapter "14.21. Unreachable Statements" of the JLS specifies, that, in general, any unreachable statement in the code is considered a compile-time-error, with the only exception being a special treatment of if-statements to specifically allow for conditional compiles.

Therefore, the only construct that may result in code elimination (if the compiler chooses to do so!) is:

if (compileTimeConstantExpression) {
    doThis(); // may be removed if compileTimeConstantExpression == false;
} else {
    doThat(); // may be removed if compileTimeConstantExpression == true;
}

(the else-part is optional, of course)

All other constructs that would allow for code elimination, like for example while (false) ..., are disallowed and cause a compile-time-error instead rather than resulting in conditional compilation.

The definition for what constitutes an acceptable compileTimeConstantExpression can be found in chapter "15.28. Constant Expressions" of the JLS. Another great page with further examples can be found here: Compile Time Constants in Java

Note: There is no requirement for a compiler to remove the "unreachable" sections of an if-stament. javac seems to do this reliably, but other compilers may not. The only way to know for sure is to check the output via decompilation, for example using javap -c as suggested by Jon Skeet.

回答2:

I have run a few tests and it seems (logically) that javac removes the code iif the condition is a constant expression that evaluates to false.

In summary, constant expressions are expressions that only use constants as operands, i.e. primitives, string literals and final primitives or Strings variables that have been initialised with a constant value.

Note that this is compiler dependent as the JLS does not force the compiler to be that smart as explained at the very bottom of 14.21:

An optimizing compiler may realize that the statement x=3; will never be executed and may choose to omit the code for that statement from the generated class file.

回答3:

I see that for 2nd example it gets removed too

this was my class

public class Test {

    public static void main(String[] args) throws Exception{
        final int VALUE = 3;
        if (VALUE > 9) System.out.println("VALUE > 9 ???");
    }
}

and this is decompiled version

Compiled from "Test.java"
public class Test extends java.lang.Object{
public Test();
  Code:
   0:   aload_0
   1:   invokespecial   #1; //Method java/lang/Object."<init>":()V
   4:   return

public static void main(java.lang.String[])   throws java.lang.Exception;
  Code:
   0:   return

}

回答4:

My guess would be that this is implementation specific (Oracle, IBM,...).

If you're interested in Oracle's version, a good place to start looking for resources would be the OpenJDK project: http://openjdk.java.net/groups/compiler/

来源：https://stackoverflow.com/questions/17965562/javac-code-elimination-capabilities

标签

java

compiler-construction

javac

dead-code

code-elimination