问题
I have tables that I've tried setting PK FK relationships on but I want to verify this. How can I show the PK/FK restraints? I saw this manual page, but it does not show examples and my google search was fruitless also. My database is credentialing1 and my constrained tables are practices and cred_insurances.
回答1:
I use
SHOW CREATE TABLE mytable;
This shows you the SQL statement necessary to receate mytable in its current form. You can see all the columns and their types (like DESC) but it also shows you constraint information (and table type, charset, etc.).
回答2:
Simply query the INFORMATION_SCHEMA:
USE INFORMATION_SCHEMA;
SELECT TABLE_NAME,
COLUMN_NAME,
CONSTRAINT_NAME,
REFERENCED_TABLE_NAME,
REFERENCED_COLUMN_NAME
FROM KEY_COLUMN_USAGE
WHERE TABLE_SCHEMA = "<your_database_name>"
AND TABLE_NAME = "<your_table_name>"
AND REFERENCED_COLUMN_NAME IS NOT NULL;
回答3:
The main problem with the validated answer is you'll have to parse the output to get the informations. Here is a query allowing you to get them in a more usable manner :
SELECT cols.TABLE_NAME, cols.COLUMN_NAME, cols.ORDINAL_POSITION,
cols.COLUMN_DEFAULT, cols.IS_NULLABLE, cols.DATA_TYPE,
cols.CHARACTER_MAXIMUM_LENGTH, cols.CHARACTER_OCTET_LENGTH,
cols.NUMERIC_PRECISION, cols.NUMERIC_SCALE,
cols.COLUMN_TYPE, cols.COLUMN_KEY, cols.EXTRA,
cols.COLUMN_COMMENT, refs.REFERENCED_TABLE_NAME, refs.REFERENCED_COLUMN_NAME,
cRefs.UPDATE_RULE, cRefs.DELETE_RULE,
links.TABLE_NAME, links.COLUMN_NAME,
cLinks.UPDATE_RULE, cLinks.DELETE_RULE
FROM INFORMATION_SCHEMA.`COLUMNS` as cols
LEFT JOIN INFORMATION_SCHEMA.`KEY_COLUMN_USAGE` AS refs
ON refs.TABLE_SCHEMA=cols.TABLE_SCHEMA
AND refs.REFERENCED_TABLE_SCHEMA=cols.TABLE_SCHEMA
AND refs.TABLE_NAME=cols.TABLE_NAME
AND refs.COLUMN_NAME=cols.COLUMN_NAME
LEFT JOIN INFORMATION_SCHEMA.REFERENTIAL_CONSTRAINTS AS cRefs
ON cRefs.CONSTRAINT_SCHEMA=cols.TABLE_SCHEMA
AND cRefs.CONSTRAINT_NAME=refs.CONSTRAINT_NAME
LEFT JOIN INFORMATION_SCHEMA.`KEY_COLUMN_USAGE` AS links
ON links.TABLE_SCHEMA=cols.TABLE_SCHEMA
AND links.REFERENCED_TABLE_SCHEMA=cols.TABLE_SCHEMA
AND links.REFERENCED_TABLE_NAME=cols.TABLE_NAME
AND links.REFERENCED_COLUMN_NAME=cols.COLUMN_NAME
LEFT JOIN INFORMATION_SCHEMA.REFERENTIAL_CONSTRAINTS AS cLinks
ON cLinks.CONSTRAINT_SCHEMA=cols.TABLE_SCHEMA
AND cLinks.CONSTRAINT_NAME=links.CONSTRAINT_NAME
WHERE cols.TABLE_SCHEMA=DATABASE()
AND cols.TABLE_NAME="table"
回答4:
afaik to make a request to information_schema you need privileges. If you need simple list of keys you can use this command:
SHOW INDEXES IN <tablename>
回答5:
Try doing:
SHOW TABLE STATUS FROM credentialing1;
The foreign key constraints are listed in the Comment column of the output.
回答6:
You can use this:
select
table_name,column_name,referenced_table_name,referenced_column_name
from
information_schema.key_column_usage
where
referenced_table_name is not null
and table_schema = 'my_database'
and table_name = 'my_table'
Or for better formatted output use this:
select
concat(table_name, '.', column_name) as 'foreign key',
concat(referenced_table_name, '.', referenced_column_name) as 'references'
from
information_schema.key_column_usage
where
referenced_table_name is not null
and table_schema = 'my_database'
and table_name = 'my_table'
回答7:
Analogous to @Resh32, but without the need to use the USE statement:
SELECT TABLE_NAME,
COLUMN_NAME,
CONSTRAINT_NAME,
REFERENCED_TABLE_NAME,
REFERENCED_COLUMN_NAME
FROM INFORMATION_SCHEMA.KEY_COLUMN_USAGE
WHERE TABLE_SCHEMA = "database_name"
AND TABLE_NAME = "table_name"
AND REFERENCED_COLUMN_NAME IS NOT NULL;
Useful, e.g. using the ORM.
回答8:
There is also a tool that oracle made called mysqlshow
If you run it with the --k keys $table_name option it will display the keys.
SYNOPSIS
mysqlshow [options] [db_name [tbl_name [col_name]]]
.......
.......
.......
· --keys, -k
Show table indexes.
example:
╰─➤ mysqlshow -h 127.0.0.1 -u root -p --keys database tokens
Database: database Table: tokens
+-----------------+------------------+--------------------+------+-----+---------+----------------+---------------------------------+---------+
| Field | Type | Collation | Null | Key | Default | Extra | Privileges | Comment |
+-----------------+------------------+--------------------+------+-----+---------+----------------+---------------------------------+---------+
| id | int(10) unsigned | | NO | PRI | | auto_increment | select,insert,update,references | |
| token | text | utf8mb4_unicode_ci | NO | | | | select,insert,update,references | |
| user_id | int(10) unsigned | | NO | MUL | | | select,insert,update,references | |
| expires_in | datetime | | YES | | | | select,insert,update,references | |
| created_at | timestamp | | YES | | | | select,insert,update,references | |
| updated_at | timestamp | | YES | | | | select,insert,update,references | |
+-----------------+------------------+--------------------+------+-----+---------+----------------+---------------------------------+---------+
+--------+------------+--------------------------+--------------+-------------+-----------+-------------+----------+--------+------+------------+---------+---------------+
| Table | Non_unique | Key_name | Seq_in_index | Column_name | Collation | Cardinality | Sub_part | Packed | Null | Index_type | Comment | Index_comment |
+--------+------------+--------------------------+--------------+-------------+-----------+-------------+----------+--------+------+------------+---------+---------------+
| tokens | 0 | PRIMARY | 1 | id | A | 2 | | | | BTREE | | |
| tokens | 1 | tokens_user_id_foreign | 1 | user_id | A | 2 | | | | BTREE | | |
+--------+------------+--------------------------+--------------+-------------+-----------+-------------+----------+--------+------+------------+---------+---------------+
来源：https://stackoverflow.com/questions/4004205/show-constraints-on-tables-command