问题
Good day guys,
I've a DOM like this
<div class="Gallery">
<div class="GaleryLeftPanel">
<img id="img1" src="/Content/Public/images/1.png" style="z-index: 100" width="141"
height="140" alt="image 1" /></div>
<div class="GalleryMiddlePanel">
<img id="img2" src="/Content/Public/images/3.png" style="z-index: 99" width="715"
height="497" alt="image 2" /></div>
<div class="GaleryRightPanel">
<img id="img3" src="/Content/Public/images/2.png" style="z-index: 98" width="140"
height="140" alt="image 2" /></div>
</div>
What I need is, If I click on img1, img2 is replaced with img1, and img3 is replaced with img2 and img1 is replaced with img3 (circular motion 1->2, 2->3, 3->1). and it continuous... and if I click on img3 then it's reverse (1<-2, 2<-3, 3<-1).
for this I'm using JQuery as follows:
$('img#img1').click(function () {
var currentScr = $(this).attr('src');
var second = $('img#img2').attr('src');
var third = $('img#img3').attr('src');
$('img#img3').attr('src', second);
$('img#img2').attr('src', currentScr);
$('img#img1').attr('src', third);
});
$('img#img3').click(function () {
var third = $(this).attr('src');
var first = $('img#img1').attr('src');
var second = $('img#img2').attr('src');
$('img#img2').attr('src', third);
$('img#img3').attr('src', first);
$('img#img1').attr('src', second);
});
It's working fine. now, What I need is, Always the 2nd image should be replace with large image instead of original image... say for example:
click on img1 (1->2L, 2->3, 3->1). here 2L is large image of img1. and click on img3 (1<-2, 2L<-3, 3<-1). here 2L is large image of img3
How to do this?, Please help me
回答1:
What you need here is to use a double ended queue data structure so you can loop through the images.
Here's a working demo - if you give me URLs to the big images I can make it work as you described.
And here's the code:
var imgs = new Array();
imgs[0] = 'http://farm7.staticflickr.com/6198/6145108610_a5d456dae4_t.jpg';
imgs[1] = 'http://farm3.staticflickr.com/2564/4064894944_34b0460fc2_t.jpg';
imgs[2] = 'http://farm1.staticflickr.com/178/460793430_1c0a085849_t.jpg';
$('#img1').click(function () {
$('#img1').attr('src', imgs[2]);
$('#img2').attr('src', imgs[0]); // - Do something here to use a larger version of the image
$('#img3').attr('src', imgs[1]);
imgs.unshift(imgs.pop());
});
$('#img3').click(function () {
$('#img1').attr('src', imgs[1]);
$('#img2').attr('src', imgs[2]); // - Do something here to use a larger version of the image
$('#img3').attr('src', imgs[0]);
imgs.push(imgs.shift());
});
And a slightly refactored version here.
EDIT:
And here's a version with big images.
var imgs = new Array();
imgs[0] = {small: 'http://farm7.staticflickr.com/6198/6145108610_a5d456dae4_t.jpg',
big: 'http://farm7.staticflickr.com/6198/6145108610_a5d456dae4_b.jpg'};
imgs[1] = {small: 'http://farm3.staticflickr.com/2564/4064894944_34b0460fc2_t.jpg',
big: 'http://farm3.staticflickr.com/2564/4064894944_34b0460fc2_b.jpg'};
imgs[2] = {small: 'http://farm9.staticflickr.com/8201/8219867682_7c9aea748f_t.jpg',
big: 'http://farm9.staticflickr.com/8201/8219867682_7c9aea748f_b.jpg'};
var $img1 = $('#img1');
var $img2 = $('#img2');
var $img3 = $('#img3');
$img1.click(function () {
$img1.attr('src', imgs[2].small);
$img2.attr('src', imgs[0].big);
$img3.attr('src', imgs[1].small);
imgs.unshift(imgs.pop());
});
$img3.click(function () {
$img1.attr('src', imgs[1].small);
$img2.attr('src', imgs[2].big);
$img3.attr('src', imgs[0].small);
imgs.push(imgs.shift());
});
回答2:
I believe you're trying to have gallery with middle picture in the high resolution.
I checked the flickr from where you took pics, and the rule seems:
- big pic: http://farm7.staticflickr.com/6198/6145108610_a5d456dae4_b.jpg
- small pic: http://farm7.staticflickr.com/6198/6145108610_a5d456dae4_t.jpg
so they differ in _t / _b only.
To implement it I updated your js part like this:
$(document).ready(function() {
var second = $('img#img2').attr('src');
$('img#img2').attr('src', swap(second));
});
function swap(img) {
if (img.indexOf("_b.") !== -1) {
return img.replace("_b.", "_t.");
} else {
return img.replace("_t.", "_b.");
}
}
$('img#img1').click(function () {
var currentScr = $(this).attr('src');
var second = $('img#img2').attr('src');
var third = $('img#img3').attr('src');
$('img#img3').attr('src', swap(second));
$('img#img2').attr('src', swap(currentScr));
$('img#img1').attr('src', third);
});
$('img#img3').click(function () {
var third = $(this).attr('src');
var first = $('img#img1').attr('src');
var second = $('img#img2').attr('src');
$('img#img2').attr('src', swap(third));
$('img#img3').attr('src', first);
$('img#img1').attr('src', swap(second));
});
Moreover (to see resolution change I made pics a bit bigger): 140/141 -> 300
jsfille link: http://jsfiddle.net/dx3DY/
Only thing seems to be that one of the sample pics doesn't seem to be in the high resolution.
回答3:
You can have the larger images for each image say 1L.png, 2L.png, 3L.png and change your script as follows:
$('img#img1').click(function () {
var currentScr = $(this).attr('src');
var second = $('img#img2').attr('src');
var third = $('img#img3').attr('src');
$('img#img3').attr('src', second.replace('1L', '1').replace('2L', '2').replace('3L', '3'));
$('img#img2').attr('src', currentScr.replace('1', '1L').replace('2', '2L').replace('3', '3L'));
$('img#img1').attr('src', third);
});
$('img#img3').click(function () {
var third = $(this).attr('src');
var first = $('img#img1').attr('src');
var second = $('img#img2').attr('src');
$('img#img2').attr('src', third.replace('1', '1L').replace('2', '2L').replace('3', '3L'));
$('img#img3').attr('src', first);
$('img#img1').attr('src', second.replace('1L', '1').replace('2L', '2').replace('3L', '3'));
});
来源：https://stackoverflow.com/questions/13563804/change-images-using-jquery-circular-motion