Human readable, recursive, sorted list of largest files

问题

What is the best practice for printing a top 10 list of largest files in a POSIX shell? There has to be something more elegant than my current solution:

DIR="."
N=10
LIMIT=512000

find $DIR -type f -size +"${LIMIT}k" -exec du {} \; | sort -nr | head -$N | perl -p -e 's/^\d+\s+//' | xargs -I {} du -h {}

where LIMIT is a file size threshold to limit the results of find.

回答1:

This uses awk to create extra columns for sort keys. It only calls du once. The output should look exactly like du.

I've split it into multiple lines, but it can be recombined into a one-liner.

du -h |
  awk '{printf "%s %08.2f\t%s\n", 
    index("KMG", substr($1, length($1))),
    substr($1, 0, length($1)-1), $0}' |
  sort -r | cut -f2,3

Explanation:

BEGIN - create a string to index to substitute 1, 2, 3 for K, M, G for grouping by units, if there's no unit (the size is less than 1K), then there's no match and a zero is returned (perfect!)
print the new fields - unit, value (to make the alpha-sort work properly it's zero-padded, fixed-length) and original line
index the last character of the size field
pull out the numeric portion of the size
sort the results, discard the extra columns

Try it without the cut command to see what it's doing.

Edit:

Here's a version which does the sorting within the AWK script and doesn't need cut (requires GNU AWK (gawk) for asorti support):

du -h |
   awk '{idx = sprintf("%s %08.2f %s", 
         index("KMG", substr($1, length($1))),
         substr($1, 0, length($1)-1), $0);
         lines[idx] = $0}
    END {c = asorti(lines, sorted);
         for (i = c; i >= 1; i--)
           print lines[sorted[i]]}'

来源：https://stackoverflow.com/questions/5213288/human-readable-recursive-sorted-list-of-largest-files

标签

Linux

shell

unix

posix