Express.js multiple methods

问题

So in Express you can do:

app.get('/logo/:version/:name', function (req, res, next) {
    // Do something
}

and

app.all('/logo/:version/:name', function (req, res) {
    // Do something
}

Is there a way to just have two methods (ie. GET and HEAD)? Such as:

app.get.head('/logo/:version/:name', function (req, res, next) {
    // Do something
}

回答1:

Just pull out the anonymous function and give it a name:

function myRouteHandler(req, res, next) {
  // Do something
}

app.get('/logo/:version/:name', myRouteHandler);
app.head('/logo/:version/:name', myRouteHandler);

Or use a general middleware function and check the req.method:

app.use('/logo/:version/:name', function(req, res, next) {
  if (req.method === 'GET' || req.method === 'HEAD') {
    // Do something
  } else
    next();
});

回答2:

You can use .route() method.

function logo(req, res, next) {
    // Do something
}

app.route('/logo/:version/:name').get(logo).head(logo);

回答3:

another version:

['get','head'].forEach(function(method){
  app[method]('/logo/:version/:name', function (req, res, next) {
    // Do something
  });
});

回答4:

You can also use the array spread operator if your route pattern is the same for multiple methods.

e.g.

const route = [
    '/logo/:version/:name', 
    function handleRequest(req, res) {
        // handle request
    }
];

app.get(...route);
app.post(...route);

来源：https://stackoverflow.com/questions/27025486/express-js-multiple-methods

标签

node.js

express