问题
I have to find corners of shapes in an image. i have used Harris corner detection algorithm to find corner, but it is giving total corners present in an image and for finding corners for a particular shape in that image it is not feasible. please suggest some other approach.
回答1:
You could use Harris corner detection algorithm. Corners are junction of two edges, where an edge is a sudden change in image brightness. This algorithm takes the differential of the corner score into account with reference to direction directly (wikipedia). Function cornerSubPix() refines the corner location - it iterates to find the sub-pixel accurate location of corners or radial saddle points (opencv documentation).
Example in code:
import cv2
import numpy as np
img = cv2.imread('edges.png')
gray = cv2.cvtColor(img, cv2.COLOR_BGR2GRAY)
gray = np.float32(gray)
dst = cv2.cornerHarris(gray,5,3,0.04)
ret, dst = cv2.threshold(dst,0.1*dst.max(),255,0)
dst = np.uint8(dst)
ret, labels, stats, centroids = cv2.connectedComponentsWithStats(dst)
criteria = (cv2.TERM_CRITERIA_EPS + cv2.TERM_CRITERIA_MAX_ITER, 100, 0.001)
corners = cv2.cornerSubPix(gray,np.float32(centroids),(5,5),(-1,-1),criteria)
for i in range(1, len(corners)):
print(corners[i])
img[dst>0.1*dst.max()]=[0,0,255]
cv2.imshow('image', img)
cv2.waitKey(0)
cv2.destroyAllWindows
to check if they are the real values you can add:
for i in range(1, len(corners)):
print(corners[i,0])
cv2.circle(img, (int(corners[i,0]), int(corners[i,1])), 7, (0,255,0), 2)
Result:
EDIT:
If you want to extract corners seperatly for every shape you could first search for contours then apply the Harris corner detection for each contour (you can draw it out on a mask with cv2.fillPolly() ). You can even define their shape based on their caracteristics (for example angle of rotation, number of corners,...). I have made an example code to help understand but note that there are other shapes that could fit the criteria I made up and you would have make other criteria (trapezoid, circle,...). This is just a simple example:
import cv2
import numpy as np
img = cv2.imread('edges.png')
gray = cv2.cvtColor(img, cv2.COLOR_BGR2GRAY)
ret,thresh = cv2.threshold(gray,150,255,cv2.THRESH_BINARY)
im2, contours, hierarchy = cv2.findContours(thresh,cv2.RETR_TREE,cv2.CHAIN_APPROX_NONE)
for i in contours:
img = cv2.imread('edges.png')
size = cv2.contourArea(i)
rect = cv2.minAreaRect(i)
if size <10000:
gray = np.float32(gray)
mask = np.zeros(gray.shape, dtype="uint8")
cv2.fillPoly(mask, [i], (255,255,255))
dst = cv2.cornerHarris(mask,5,3,0.04)
ret, dst = cv2.threshold(dst,0.1*dst.max(),255,0)
dst = np.uint8(dst)
ret, labels, stats, centroids = cv2.connectedComponentsWithStats(dst)
criteria = (cv2.TERM_CRITERIA_EPS + cv2.TERM_CRITERIA_MAX_ITER, 100, 0.001)
corners = cv2.cornerSubPix(gray,np.float32(centroids),(5,5),(-1,-1),criteria)
if rect[2] == 0 and len(corners) == 5:
x,y,w,h = cv2.boundingRect(i)
if w == h or w == h +3: #Just for the sake of example
print('Square corners: ')
for i in range(1, len(corners)):
print(corners[i])
else:
print('Rectangle corners: ')
for i in range(1, len(corners)):
print(corners[i])
if len(corners) == 5 and rect[2] != 0:
print('Rombus corners: ')
for i in range(1, len(corners)):
print(corners[i])
if len(corners) == 4:
print('Triangle corners: ')
for i in range(1, len(corners)):
print(corners[i])
if len(corners) == 6:
print('Pentagon corners: ')
for i in range(1, len(corners)):
print(corners[i])
img[dst>0.1*dst.max()]=[0,0,255]
cv2.imshow('image', img)
cv2.waitKey(0)
cv2.destroyAllWindows
Output (after all shapes are detected):
回答2:
For every shape, trace the contour, and for every pixel of the contour, check if a nearby corner was found (say in a 3x3 or 5x5 neighborhood).
来源:https://stackoverflow.com/questions/50984205/how-to-find-corners-points-of-a-shape-in-an-image-in-opencv