Is there a generic way for a function to reference itself?

Question

I can access a python function's attribute inside of function itself by below code:

def aa():
    print aa.__name__
    print aa.__hash__
    # other simliar

However, if above aa() function is a template for write other code, say bb(), I have to write:

def bb():
    print bb.__name__
    print bb.__hash__
    # other simliar

Is there a "pointer" similar to the self argument in a class method so I could write code like this?

def whatever():
    print self.__name__
    print self.__hash__
    # other simliar

I searched and found someone said to use the class to solve this problem, but that may be a trouble to redefine all the existing functions. Any suggestions?

Answer 1

There is no generic way for a function to refer to itself. Consider using a decorator instead. If all you want as you indicated was to print information about the function that can be done easily with a decorator:

from functools import wraps
def showinfo(f):
    @wraps(f)
    def wrapper(*args, **kwds):
         print(f.__name__, f.__hash__)
         return f(*args, **kwds)
    return wrapper

@showinfo
def aa():
    pass

If you really do need to reference the function, then just add it to the function arguments:

def withself(f):
    @wraps(f)
    def wrapper(*args, **kwds):
        return f(f, *args, **kwds)
    return wrapper

@withself
def aa(self):
      print(self.__name__)
      # etc.

Edit to add alternate decorator:

You can also write a simpler (and probably faster) decorator that will make the wrapped function work correctly with Python's introspection:

def bind(f):
    """Decorate function `f` to pass a reference to the function
    as the first argument"""
    return f.__get__(f, type(f))

@bind
def foo(self, x):
    "This is a bound function!"
    print(self, x)


>>> foo(42)
<function foo at 0x02A46030> 42
>>> help(foo)
Help on method foo in module __main__:

foo(self, x) method of builtins.function instance
    This is a bound function!

This leverages Python's descriptor protocol: functions have a __get__ method that is used to create bound methods. The decorator simply uses the existing method to make the function a bound method of itself. It will only work for standalone functions, if you wanted a method to be able to reference itself you would have to do something more like the original solution.

Answer 2

http://docs.python.org/library/inspect.html looks promising:

import inspect
def foo():
     felf = globals()[inspect.getframeinfo(inspect.currentframe()).function]
     print felf.__name__, felf.__doc__

you can also use the sys module to get the name of the current function:

import sys
def bar():
     felf = globals()[sys._getframe().f_code.co_name]
     print felf.__name__, felf.__doc__

Answer 3

How about a quick hack to make your own "self" name, like this:

>>> def f():
...     self = f
...     print "My name is ", self.__name__, "and I am", self.__hash__
...
>>> f()
My name is  f and I am <method-wrapper '__hash__' of function object at 0x00B50F30>
>>> x = f
>>> x()
My name is  f and I am <method-wrapper '__hash__' of function object at 0x00B50F30>
>>>