Sorting a text file alphabetically (Python)

问题

I would like to sort the file 'shopping.txt' in alphabetical order

shopping = open('shopping.txt')
line=shopping.readline()
while len(line)!=0:
    print(line, end ='')
    line=shopping.readline()
#for eachline in myFile:
#    print(eachline)
shopping.close()

回答1:

Just to show something different instead of doing this in python, you can do this from a command line in Unix systems:

sort shopping.txt -o shopping.txt

and your file is sorted. Of course if you really want python for this: solution proposed by a lot of other people with reading file and sorting works fine

回答2:

An easy way to do this is using the sort() or sorted() functions.

lines = shopping.readlines()
lines.sort()

Alternatively:

lines = sorted(shopping.readlines())

The disadvantage is that you have to read the whole file into memory, though. If that's not a problem, you can use this simple code.

回答3:

Use sorted function.

with open('shopping.txt', 'r') as r:
    for line in sorted(r):
        print(line, end='')

来源：https://stackoverflow.com/questions/27123125/sorting-a-text-file-alphabetically-python