问题
Here is my code:
#include <iostream>
using namespace std;
int main(){
char inp[5], out[4];
cin >> inp >> out;
cout << inp << endl;
cout << out << endl;
system("pause");
return 0;
}
when I type:
12345 6789
It gives me:
6789
Why I failed to save the 5 words char array 'inp' and it showed nothing? The second input looks normal though. However, when I set out[3] or out[5], it seems to work alright? It seem that two char array of [5] then followed by [4] would cause problem...
回答1:
I see that you enter (type) 1234567890
characters to input data for inp[5]
- it is a problem because imp
array is able to store 4 characters and null-terminator. When cin >> inp
store more than 4 characters to inp
array it leads to problem with data (somthing like undefined behaviour). So solution can be in allocation more memory for data, e.g.:
#include <iostream>
using namespace std;
int main(){
char inp[15], out[15]; // more memory
cin >> inp >> out;
cout << inp << endl;
cout << out << endl;
system("pause");
return 0;
}
来源:https://stackoverflow.com/questions/29477567/using-cin-for-char-array