问题
I want the output as a matrix in a binary format but I keep getting it as a single long array. Can anyone suggest where I am going wrong
program ascii_to_binary
implicit none
c
c declarations
integer iw,jy,i
real A(47,52),z(47,52),undef
real x(47,52)
logical exist
c----------------------------------------------------
c read in the index, insert name of file in input_file
undef = -9999.
c read in the index, insert name of file in input_file
inquire(file="weekly_mean_sce.txt", exist=exist)
if (exist) then
print *,"Exist"
open(43,file='weekly_mean_sce.txt',status='old')
do jy=1,47
read(43,*) A(jy,:)
enddo
print *, maxval(A)
write(6,*)'read in input data'
else
print *,"not there"
end if
x=reshape(A,(/47,52/))
OPEN(UNIT=15, FILE="sce.dat",ACTION="write")
do i=1,47
write(15, '(F9.2)')( real(x(i,iw)) ,iw=1,52)
end do
write(15,"(F9.2)") x(1:47,1:52)
END PROGRAM ascii_to_binary
回答1:
Normal Fortran I/O uses a record structure. If you want unformatted I/O while keeping the record structure, I would recommend
open(15,file="sce.dat", form="unformatted")
do iw=1,52 ! Better to use named constants here
write (15) x(:,iw)
end do
This writes out the values in the natural Fortran array order, where the storage order is a(1,1), a(2,1) etc, plus some additional information (record markers) to identify where a record starts and where it ends.
If you do not need the record structure, you can just use
open(15,file="sce.dat",form="unformatted",access="stream")
write (15) x
来源:https://stackoverflow.com/questions/29225562/output-as-a-matrix-in-fortran