问题
If I have a variable that is optional, and I only want to have it search on it if it is defined, I know that I can do this, but is there a way to define the function elsewhere, so I don't need to rewrite the same anonymous function over and over again? Or are the any other good alternatives to going about solving this problem?
.......->where(function($query) use ($gender){
if ($gender) {
$query->where('gender', '=', $gender);
}
})->get();
回答1:
You could use a dynamic scope
class User extends Eloquent {
public function scopeGender($query, $gender)
{
if ($gender) {
return $query->whereGender($gender);
}
return $query;
}
}
Then throughout your application
...->gender($gender)->get();
回答2:
Since Laravel 5.2.27, you can use conditional clauses
For example:
->when($gender, function($query) use ($gender) {
$query->where('gender', '=', $gender);
})
->get();
来源:https://stackoverflow.com/questions/26750285/eloquent-conditional-where-filter