问题
I have a video chat requirement wherein I have to connect 2 (somewhat related) users through video chat. I am not finding necessary api to call, hence the question.
I am basically following this tutorial but it seems it doesn't have everything I need. I do not need explicit "call to this user" sort of function. The user never gets to see entire user list.
As a result, I wonder if I could have X number of users calling and another X number of users waiting to accept that call.
To summarize:
I just want to connect users based on some traits (like their registered tags). For any user A, there can be more than one users having similar tags as A - so all of them are prospect video chat users for user A.
I need to pick one of them (random may work) and stream A's video / audio among them.
What all things do I have to do? Here is partial list but I don't know I am right at the end.
1 - Call [QBAuth createSessionWithDelegate:self]
2 - From the resulting session, call [QBUsers logInWithUserLogin]
3 - From the resulting session, call [[QBChat instance] loginWithUser:user]
4 - From the resulting chatDidLogin delegate, call what?
Should it be entering some chat room, or use of some code using chatRoomDidChangeOnlineUsers? I don't know.
Please help me with the minimal required sequence of things to call, in short, modify 1-2-3-4 above.
Update on why it would not be possible to initiate a call:
This is because since chat is involuntary, calls may collide. If I use calluser api, everyone would end up calling. Likewise is true for waiting to accept a call. I am unable to think of a fair strategy wherein the system does not get overwhelmed with call requests, or silent due to everyone keeps waiting.
In other words I am for the solution wherein every user can pick a random person to call, but does not mind if someone else calls him, and he should be able to handle it gracefully.
回答1:
First of all you should register new user and send him some tag. To do this you have to:
1) Create a session
[QBAuth createSessionWithDelegate:self]
2) Register new User and set him some tag:
QBUUser *user = [QBUUser user]; user.login = @"someuser"; user.password = @"somepass"; user.tags = @[@"Tag1"];
3) Create more users with the same tag
Next, in order to have a call with some user you have to randomly get it. Here is a request to get all the users with particular tag:
[QBUsers usersWithTags:@[@"Tag1"] delegate:self];
you will get all users with this tag. Next - choose one of them randomly
Finally, make a video call to this user
Use Users sample to learn how to work with Users module http://quickblox.com/developers/SimpleSample-users-ios
btw: QuickBlox released SDK 2.0 with new blocks API - you can try it http://quickblox.com/developers/IOS#iOS_SDK_Transition_guide_from_version_1.9_to_2.0
来源：https://stackoverflow.com/questions/24764844/quickblox-ios-connecting-2-users-in-video-chat-without-initiating-a-call