问题
Multiplication of sparse tensors with themselves or with dense tensors does not seem to work in TensorFlow. The following example
from __future__ import print_function
import tensorflow as tf
x = tf.constant([[1.0,2.0],
[3.0,4.0]])
y = tf.SparseTensor(indices=[[0,0],[1,1]], values=[1.0,1.0], shape=[2,2])
z = tf.matmul(x,y)
sess = tf.Session()
sess.run(tf.initialize_all_variables())
print(sess.run([x, y, z]))
fails with the error message
TypeError: Input 'b' of 'MatMul' Op has type string that does not match type
float32 of argument 'a'
Both tensors have values of type float32 as seen by evaluating them without the multiplication op. Multiplication of y with itself returns a similar error message. Multipication of x with itself works fine.
回答1:
General-purpose multiplication for tf.SparseTensor is not currently implemented in TensorFlow. However, there are three partial solutions, and the right one to choose will depend on the characteristics of your data:
If you have a
tf.SparseTensorand atf.Tensor, you can use tf.sparse_tensor_dense_matmul() to multiply them. This is more efficient than the next approach if one of the tensors is too large to fit in memory when densified: the documentation has more guidance about how to decide between these two methods. Note that it accepts atf.SparseTensoras the first argument, so to solve your exact problem you will need to use theadjoint_aandadjoint_barguments, and transpose the result.If you have two sparse tensors and need to multiply them, the simplest (if not the most performant) way is to convert them to dense and use
tf.matmul:a = tf.SparseTensor(...) b = tf.SparseTensor(...) c = tf.matmul(tf.sparse_tensor_to_dense(a, 0.0), tf.sparse_tensor_to_dense(b, 0.0), a_is_sparse=True, b_is_sparse=True)Note that the optional
a_is_sparseandb_is_sparsearguments mean that "a(orb) has a dense representation but a large number of its entries are zero", which triggers the use of a different multiplication algorithm.For the special case of sparse vector by (potentially large and sharded) dense matrix multiplication, and the values in the vector are 0 or 1, the tf.nn.embedding_lookup operator may be more appropriate. This tutorial discusses when you might use embeddings and how to invoke the operator in more detail.
For the special case of sparse matrix by (potentially large and sharded) dense matrix, tf.nn.embedding_lookup_sparse() may be appropriate. This function accepts one or two
tf.SparseTensorobjects, withsp_idsrepresenting the non-zero values, and the optionalsp_weightsrepresenting their values (which otherwise default to one).
回答2:
Recently, tf.sparse_tensor_dense_matmul(...) was added that allows multiplying a sparse matrix by a dense matrix.
https://www.tensorflow.org/versions/r0.9/api_docs/python/sparse_ops.html#sparse_tensor_dense_matmul
https://github.com/tensorflow/tensorflow/issues/1241
回答3:
It seems that
tf.sparse_matmul(
a,
b,
transpose_a=None,
transpose_b=None,
a_is_sparse=None,
b_is_sparse=None,
name=None
)
is not for multiplication of two SparseTensors.
a and b are Tensors not SparseTensors. And I have tried that, it is not working with SparseTensors.
回答4:
tf.sparse_matmul is for multiplying two dense tensor not sparse type of data structure. That function is just an optimized version of tensor multiplication if the given matrix (or both two matrixes) have many zero value. Again it does not accept sparse tensor data type. It accepts dense tensor data type. It might fasten your calculations if values are mostly zero.
as far as I know there is no implementation of two sparse type tensor muliplication. but just one sparse one dense which is tf.sparse_tensor_dense_matmul(x, y) !
回答5:
To make the answer more complete:
tf.sparse_matmul(
a,
b,
transpose_a=None,
transpose_b=None,
a_is_sparse=None,
b_is_sparse=None,
name=None
)
exists as well:
https://www.tensorflow.org/api_docs/python/tf/sparse_matmul
来源:https://stackoverflow.com/questions/34030140/is-sparse-tensor-multiplication-implemented-in-tensorflow