问题
a = 1
print hex(a)
The above gives me the output: 0x1
How do I get the output as 0x01 instead?
回答1:
You can use format :
>>> a = 1
>>> '{0:02x}'.format(a)
'01'
>>> '0x{0:02x}'.format(a)
'0x01'
回答2:
>>> format(1, '#04x')
'0x01'
回答3:
Try:
print "0x%02x" % a
It's a little hairy, so let me break it down:
The first two characters, "0x" are literally printed. Python just spits them out verbatim.
The % tells python that a formatting sequence follows. The 0 tells the formatter that it should fill in any leading space with zeroes and the 2 tells it to use at least two columns to do it. The x is the end of the formatting sequence and indicates the type - hexidecimal.
If you wanted to print "0x00001", you'd use "0x%05x", etc.
回答4:
print "0x%02x"%a
x as a format means "print as hex".02 means "pad with zeroes to two characters".
回答5:
You can use format:
>>> "0x"+format(1, "02x")
'0x01'
来源：https://stackoverflow.com/questions/28650857/integer-to-hexadecimal-conversion-in-python