问题
I have two entities:
@Entity
public class Customer implements java.io.Serializable {
...
@OneToMany(fetch=FetchType.EAGER, mappedBy="customer")
private Set<CustomerOrder> customerOrders;
...
@Entity
public class CustomerOrder implements java.io.Serializable {
....
private double cost;
@ManyToOne
@JoinColumn(name="CUST_ID")
public Customer customer;
...
Now in my JPQL, I want to return those customers with their CustomerOrder.cost>1000. For example, there are three customers A, B and C. A has two orders with cost=1000 and 2000 respectively. B has three orders with cost=2000,3000 and 500 respectively. C has one order with cost=500. Now i want to get the three customers: A returns the orders with cost=2000 only; B returns the orders with 2000 and 3000; C returns an empty orders collection.
But the following will always return the full collection:
select c from Customer c, in(c.customerOrders) o where o.cost>1000
How can I do that in JPQL or in Hibernate in particular?
回答1:
The query posted is equivalent to
select c from Customer c inner join c.customerOrders o where o.cost > 1000
which simply returns all customers that have at least one order with cost greater than 1000.
I would suggest to inverse join and select orders - it's semantically the same but structurally different from your desired result though:
select o from CustomerOrder o where o.cost > 1000
Now, Hibernate has non-JPA feature called Filter that should accomplish exactly what you are looking for - see here: http://www.hibernate.org/hib_docs/reference/en/html/filters.html
回答2:
Try this
select c from Customer c join CustomerOrder o with o.cost > 1000
It may return a customer twice if he has two orders having cost > 1000, for which you can do group by
select c from Customer c join CustomerOrder o with o.cost > 1000
group by c
回答3:
Sounds like a bad idea (performance-wise) to have OneToMany-relation there.
But why doesn't this work: select o from CustomerOrder o where o.cost > 1000;
then from the result list extract the Customer's?
来源:https://stackoverflow.com/questions/675979/how-to-filter-collection-in-jpa-jpql