Java/android how to start an AsyncTask after 3 seconds of delay?

问题

How can an AsyncTask be started after a 3 second delay?

回答1:

You can use Handler for that. Use postDelayed(Runnable, long) for that.

Handler#postDelayed(Runnable, Long)

回答2:

Using handlers as suggested in the other answers, the actual code is:

new Handler().postDelayed(new Runnable() {
    @Override
    public void run() {
        new MyAsyncTask().execute();
    }
}, 3000);

回答3:

You can use this piece of code to run after a 3 sec delay.

new Timer().schedule(new TimerTask() {          
    @Override
    public void run() {

        // run AsyncTask here.    


    }
}, 3000);

回答4:

Use Handler class, and define Runnable handleMyAsyncTask that will contain code executed after 3000 msec delay:

mHandler.postDelayed(handleMyAsyncTask, 1000*3);

来源：https://stackoverflow.com/questions/4177409/java-android-how-to-start-an-asynctask-after-3-seconds-of-delay