问题
I have a file which contains multiple serialized objects of class XYZ. While serializing, the each XYZ object was appended to the file.
Now I need to read each object from the file, and I am able to read only the first object.
Any idea how I can read each object from the file and eventually store it into a List?
回答1:
Try the following:
List<Object> results = new ArrayList<Object>();
FileInputStream fis = new FileInputStream("cool_file.tmp");
ObjectInputStream ois = new ObjectInputStream(fis);
try {
while (true) {
results.add(ois.readObject());
}
} catch (OptionalDataException e) {
if (!e.eof)
throw e;
} finally {
ois.close();
}
Following up on Tom's brilliant comment, the solution for multiple ObjectOutputStream
s would be,
public static final String FILENAME = "cool_file.tmp";
public static void main(String[] args) throws IOException, ClassNotFoundException {
String test = "This will work if the objects were written with a single ObjectOutputStream. " +
"If several ObjectOutputStreams were used to write to the same file in succession, " +
"it will not. – Tom Anderson 4 mins ago";
FileOutputStream fos = null;
try {
fos = new FileOutputStream(FILENAME);
for (String s : test.split("\\s+")) {
ObjectOutputStream oos = new ObjectOutputStream(fos);
oos.writeObject(s);
}
} finally {
if (fos != null)
fos.close();
}
List<Object> results = new ArrayList<Object>();
FileInputStream fis = null;
try {
fis = new FileInputStream(FILENAME);
while (true) {
ObjectInputStream ois = new ObjectInputStream(fis);
results.add(ois.readObject());
}
} catch (EOFException ignored) {
// as expected
} finally {
if (fis != null)
fis.close();
}
System.out.println("results = " + results);
}
回答2:
You can't append ObjectOutputStreams to a file. They contain headers as well as the objects you wrote. Revise your technique.
Also your EOF detection is wrong. You should catch EOFException separately. OptionalDataException means something different entirely.
回答3:
this works for me
System.out.println("Nombre del archivo ?");
nArchivo= sc.next();
sc.nextLine();
arreglo=new ArrayList<SuperHeroe>();
try{
FileInputStream fileIn = new FileInputStream(nArchivo);
ObjectInputStream in = new ObjectInputStream(fileIn);
while(true){
arreglo.add((SuperHeroe) in.readObject());
}
}
catch(IOException i)
{
System.out.println("no hay mas elementos\n elementos cargados desde el archivo:" );
for(int w=0;w<arreglo.size();w++){
System.out.println(arreglo.get(w).toString());
}
}catch(ClassNotFoundException c)
{
System.out.println("No encontre la clase Estudiante !");
c.printStackTrace();
return;
}
回答4:
You can follow the below mentioned code for handling end of file differently:
public static void main(String[] args) throws FileNotFoundException, IOException, ClassNotFoundException {
// TODO Auto-generated method stub
ObjectOutputStream oos = new ObjectOutputStream(new FileOutputStream("E://sample.txt"));
oos.writeObject(new Integer(5));
oos.writeObject(new Integer(6));
oos.writeObject(new Integer(7));
oos.writeObject(new Integer(8));
oos.flush();
oos.close();
ObjectInputStream ios = new ObjectInputStream(new FileInputStream("E://sample.txt"));
Integer temp;
try {
while ((temp = (Integer) ios.readObject()) != null) {
System.out.println(temp);
}
} catch (EOFException e) {
} finally {
ios.close();
}
}
It will write and read multiple integer objects from the file without throwing any exception.
来源:https://stackoverflow.com/questions/7826834/de-serializing-objects-from-a-file-in-java