To understand a line of PHP code about a connection

问题

What is connection() in the following code?

Code which I do understand completely

if($user->connection($email,$password)){
}

---

Let's assume connection() is pseudo-code. Is the pg_prepare and pg_execute` enough to create the connection?

---

The line caused me to omit the use of its main code in generating a login system. Subsequently, SOers pointed out severe sequrity holes in my code.

I could not find the explanation for the function connection(). The code seems to be pseudo-code to me, since the connection does not have any attributes to the database, for instance by

Example of how the connection should be formed

     $result = pg_prepare($dbconn, "query22", "SELECT passhash_md5 FROM users
         WHERE email=$1;");                                             
     $passhash_md5 = pg_execute($dbconn, "query22", array($_REQUEST['email']));                 

回答1:

$user is an instance of a class.

connection is a method in that class.

$mail & $password are parameters to that method.

This has nothing todo with arrays. what you mean would be:

$foo = array("key" => "value");

maybe this can help you: http://www.webstockbox.com/php/7-tutorials-on-how-to-create-a-php-login-system/

回答2:

I haven't actually used php.net, but this just looks like connection is a method of object $user that takes 2 params. Nothing to do with arrays.

来源：https://stackoverflow.com/questions/1266847/to-understand-a-line-of-php-code-about-a-connection