问题
I have a noSql (Cloudant) database
-Within the database we have documents where one of the document fields represents “table” (type of document)
-Within the documents we have fields that represent links other documents within the database
For example:
{_id: 111, table:main, user_id:222, field1:value1, other1_id: 333}
{_id: 222, table:user, first:john, other2_id: 444}
{_id: 333, table:other1, field2:value2}
{_id: 444, table:other2, field3:value3}
We want of way of searching for _id:111
And the result be one document with data from linked tables:
{_id:111, user_id:222, field1:value1, other1_id: 333, first:john, other2_id: 444, field2:value2, field3:value3}
Is there a way to do this?
There is flexibility on the structure of how we store or get the data back—any suggestions on how to better structure the data to make this possible?
回答1:
The first thing to say is that there are no joins in Cloudant. If you're schema relies on lots of joining then you're working against the grain of Cloudant which may mean extra complication for you or performance hits.
There is a way to de-reference other documents' ids in a MapReduce view. Here's how it works:
- create a MapReduce view to emit the main document's body and its linked document's ids in the form
{ _id: 'linkedid'}
- query the view with
include_docs=true
to pull back the document AND the de-referenced ids in one go
In your case, a map function like this:
function(doc) {
if (doc.table === 'main') {
emit(doc._id, doc);
if (doc.user_id) {
emit(doc._id + ':user', { _id: doc.user_id });
}
}
}
would allow you to pull back the main document and its linked user document in one API by hitting the GET /mydatabase/_design/mydesigndoc/_view/myview?startkey="111"&endkey="111z"&include_docs=true
endpoint:
{
"total_rows": 2,
"offset": 0,
"rows": [
{
"id": "111",
"key": "111",
"value": {
"_id": "111",
"_rev": "1-5791203eaa68b4bd1ce930565c7b008e",
"table": "main",
"user_id": "222",
"field1": "value1",
"other1_id": "333"
},
"doc": {
"_id": "111",
"_rev": "1-5791203eaa68b4bd1ce930565c7b008e",
"table": "main",
"user_id": "222",
"field1": "value1",
"other1_id": "333"
}
},
{
"id": "111",
"key": "111:user",
"value": {
"_id": "222"
},
"doc": {
"_id": "222",
"_rev": "1-6a277581235ca01b11dfc0367e1fc8ca",
"table": "user",
"first": "john",
"other2_id": "444"
}
}
]
}
Notice how we get two rows back, the first is the main document body, the second the linked user.
来源:https://stackoverflow.com/questions/43825864/how-to-do-a-nosql-linked-query