Parse error: syntax error, unexpected (T_STRING), expecting variable (T_VARIABLE) [closed]

问题

I will be grateful if someone can point out where the error is occurring.

class hotel extends WishDBxyz{ 
 public nomhotel;
 protected idhotel, ile_idile, pays_idpays, chainehotel_idchainehotel, actif ;
}

Just on second line got the error Parse error: syntax error, unexpected (T_STRING), expecting variable (T_VARIABLE). I'm quite new to Object Oriented PHP and writting one class inheriting another class.

回答1:

Those are variables in php.So add the $ sign:

class hotel extends WishDBxyz{ 
 public $nomhotel;
 protected $idhotel, $ile_idile, $pays_idpays, $chainehotel_idchainehotel, $actif ;
}

回答2:

you are missing the $

public $var;

see http://www.php.net/manual/en/language.oop5.basic.php

回答3:

You are missing $ in variables

class hotel extends WishDBxyz{ 
 public $nomhotel;
 protected $idhotel, $ile_idile, $pays_idpays, $chainehotel_idchainehotel, $actif ;
}

回答4:

From the PHP manual page:

Variables in PHP are represented by a dollar sign followed by the name of the variable. The variable name is case-sensitive.

So for your case, you'd put something like:

class Hotel extends WishDBxyz{ 
    public $nomhotel;
    protected $idhotel, $ile_idile, $pays_idpays, $chainehotel_idchainehotel, $actif ;
}

For examples on declaring classes, properties, methods, etc., look at the PHP manual.

(As a habit, I usually use UpperCamelCase for the class name)

回答5:

Variable names should be prefixed with $

来源：https://stackoverflow.com/questions/21930748/parse-error-syntax-error-unexpected-t-string-expecting-variable-t-variable

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