Convert Military Time to Standard Time Error

问题

I have a data set that pulls back visit time in hour/min format (e.g. - 12:33PM would be 1233). I am trying to use the DATEPART function but it keeps giving me a syntax error stating that :

"expecting something between '(' and the 'HOUR' keyword.

The section below is the piece of the SQL that is giving me errors:

CASE WHEN DATEPART(HOUR , VSL.VISIT_TIME) > 12  THEN DATEPART (HOUR, VSL.VISIT_TIME) -12 ELSE DATEPART (HOUR, VSL.VISIT_TIME) END AS THE_TIME

I am trying to just get the hour part of the time.

回答1:

Doing this through a series of casts, you could do something like:

SELECT CAST(CAST(CAST(CAST((1420 * 100 (FORMAT '99:99:99')) AS CHAR(8)) AS time ) AS TIME FORMAT 'HH:MIBT') AS CHAR(8))

Or you could use some math to sort it out and cast at the end:

SELECT 
  1420 AS intTime,
  FLOOR(intTime/100) AS intHours,
  intTime - (intHours * 100) AS intMinutes,
  intHours * 60 + intMinutes AS totalIntMinutes,
  TIME '00:00:00' + (totalIntMinutes * INTERVAL '1' MINUTE) AS totalTime,
  CAST(CAST(totalTime AS TIME FORMAT 'HH:MIBT') AS CHAR(8)) AS char12HrTime

Or just parse and math the thing:

SELECT 
  1420 AS intTime,
  Trim(CASE WHEN FLOOR(intTime/100) > 12 then FLOOR(intTime/100) - 12 ELSE FLOOR(intTime/100) END) || ':' || TRIM(intTime - (FLOOR(intTime/100) * 100))

There's probably a few other ways to cut this up, perhaps a little more elegantly.

Either way you cut it this is going to be a little ugly since you are storing time as something other than a time type.

来源：https://stackoverflow.com/questions/51200255/convert-military-time-to-standard-time-error

标签

sql

teradata

datepart