问题
I'm trying to create Swift OS X app now, and found difficulty using ScriptingBridge.
I included proper iTunes.h file, and Xcode is not giving any error when I wrote "iTunesApplication" as type.
However, when I compile(run) the app, it gives me error :( Does anybody know about this issue?
Undefined symbols for architecture x86_64:
"_OBJC_CLASS_$_iTunesApplication", referenced from:
__TFC12LoveYouChloe11AppDelegate10showWindowfS0_FPSs9AnyObject_T_ in AppDelegate.o
ld: symbol(s) not found for architecture x86_64
clang: error: linker command failed with exit code 1 (use -v to see invocation)
And here is my code:
var iTunes: iTunesApplication = SBApplication.applicationWithBundleIdentifier("com.apple.iTunes") as iTunesApplication
iTunes.playpause()
回答1:
The best way to solve this is to take the generated Objective-C Scripting Bridge header and convert it into a native Swift. I wrote a Python script (here) that can do that for you. You can see my answer here for a better explanation of what exactly is going on if you're interested.
回答2:
Instead of
var iTunes: iTunesApplication = SBApplication.applicationWithBundleIdentifier("com.apple.iTunes")
use
var iTunes: AnyObject = SBApplication.applicationWithBundleIdentifier("com.apple.iTunes")
Sometimes the compiler gets confused when you are accessing two or more properties in a row(no idea why) so you may need to use a temporary variable. E.g.:
Instead of:
let songName: String = iTunes.playlists[0].songs[0].name
Try:
let song: AnyObject = iTunes.playlists[0].songs[0]
let songName = song.name
Or Alternatively the faster (this also works if you declare iTunes as an SBApplication) :
let songName: String = iTunes.valueAtIndex(0, inPropertyWithKey: "playlists").valueAtIndex(0, inPropertyWithKey: "songs").valueForKey("name")
EDIT: You can also generate the .swift headers as specified here: https://github.com/tingraldi/SwiftScripting
来源：https://stackoverflow.com/questions/27395805/swift-undefined-symbols-itunesapplication