问题
I feel like I should be really close, but I can't get this to work just quite right.
I'm sending an image using filetransfer from my phonegap app to my rails app (3.1.1 ruby 1.8.7 btw).
I want to write the file to the filesystem.
This is the params hash:
Parameters: {"file"=>#<ActionDispatch::Http::UploadedFile:0x7f1e2baa94e8 @tempfile=#<File:/tmp/RackMultipart20120607-5707-owzii5-0>,
@headers="Content-Disposition: form-data; name=\"file\"; filename=\"image.jpg\"\r\nContent-Type: image/jpeg\r\n",
@content_type="image/jpeg", @original_filename="image.jpg">}
Basically, I can access the file through params[:file]. Now I need to just write that image on to my filesystem. I don't have a model for the image to correspond to, so I don't really need paperclip. Right now, the best I could come up with is this:
open(params[:file]) do |image|
File.open("theiamge.jpg","wb"){|file| file.puts image.read }
end
This is the error I get:
TypeError (can't convert ActionDispatch::Http::UploadedFile into String):
EDIT:
So, this is rather odd. I can get these commands working in my irb:
File.open('newimage.jpg', 'wb') do |f|
f.write File.open('oldimage.jpg').read
end
However, this doesn't work:
File.open("ihatedetails.jpg",'wb') do |f|
f.write File.open(params[:file]).read
end
I get this error: TypeError (can't convert ActionDispatch::Http::UploadedFile into String):
I'm using ruby 1.9.3 in my irb, but these commands should be the same...
So I'm stumped right now.
回答1:
The code should be:
File.open("ihatedetails.jpg",'wb') do |f|
f.write params[:file].read
end
or File.open("ihatedetails.jpg",'wb') { |f| f.write params[:file].read }
in one line.
来源:https://stackoverflow.com/questions/10942930/how-to-write-an-image-to-filesystem-in-rails-3-1-1